Let R be the region bounded by the following curves. Use the disk or washer method to find the volume of the solid generated whe n R is revolved about the y-axis. y= square root of (x/2) , y=0 , x=2
1 answer:
Answer:
3.2 pi
Step-by-step explanation:
Given 3 curves are:
y = square root ( x / 2)
y = 0
x = 2
Use washer method for hollow volumes.
Step 1: Compute A (y)
A ( y ) = pi * ( f_1 (y) ^2 - f_2 (y) ^2)
where,
f_1 (y) is the function further away from y axis
f_2 (y) is the function closer to y axis
f_1 (y) = 2
f_2 (y) = 2*y^2
A ( y ) = pi * ( 2 ^2 - (2*y) ^2)
A (y) = pi * (4 - 4*y^2)
A (y) = 4*pi * (1 - y^2)
Step 2: Compute V (y)
Answer: V = 3.2 pi
You might be interested in
diameter=30km,radius=30\2=15km circumference=2 pi xradius =30pi
Well,first you have to calculate the loss on both stocks.Then you need to sum them up and find his totall loss.Finally, you have to tutn it to prescentace. Your result is about 16.2%(I figured it might not be distinguishable in the picture I sent you.)
Answer:
x = 1
Step-by-step explanation:
########### #### ## ######## ###