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aniked [119]
3 years ago
7

Segment AB is congruent to segment AB. This statement shows the ______ property. reflexive symmetric transitive substitution

Mathematics
2 answers:
svlad2 [7]3 years ago
4 0

Answer: Reflective

Step-by-step explanation:

balu736 [363]3 years ago
4 0

Answer:

the answer is reflective

Step-by-step explanation:

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Solve for the value of x.​
gulaghasi [49]

Answer:

40°

Step-by-step explanation:

It's half the angle at the centre

½×80 = 40

7 0
3 years ago
Read 2 more answers
In a normal bell shaped curve, approximately which percentage of scores fall within 3 standard deviation (-3 to +3) or blank (34
Leokris [45]

Let x represent the scores. With mean and standard deviation given,

The Empirical rule states that

1) About 68% of the x values lie between 1 standard deviation below and above the mean

2) About 95% of the x values lie between 2 standard deviation below and above the mean

3) About 99.7% of the x values lie between 3 standard deviation below and above the mean

If we consider this rule, then the percentage of scores that fall within 3 standard deviation (-3 to +3) is 99% because this is closer to 99.7%

5 0
11 months ago
Complete the table below to find solutions to the linear equation 4x + y = -40.
Pepsi [2]

Answer:

(1,-44), (2,-48),(3,-52).......

Step-by-step explanation:

4(1)+y=-40

4+y=-40

y=-40-4

y=-44

(1,-44)

.

.

.

4 0
2 years ago
A box is being created out of a 15 inch by 10 inch sheet of metal. Equal-sized squares are cutout of the corners, then the sides
ivolga24 [154]

Answer:

Therefore the dimensions of the square should be 0.1528 inch by 0.1528 inch so, the box  has largest volume.

Step-by-step explanation:

Given that,

A box is being created out of a 15 inches by 10 inches sheet of metal.

The length of the one side of the squares which are cut out of the each corners of the metal sheet be x.

The length of the metal box be = (15-2x) inches.

The width of the metal box be =(10-2x) inches

The height of the metal box be =x inches

Then, the volume of the metal box= length×width×height

                                                         =(15-2x)(10-2x)x cubic inches

                                                         =(150x-50x²+4x³) cubic inches

∴ V= 4x³-50x²+15x

Differentiating with respect to x

V'=12x²-100x+15

Again differentiating with respect to x

V''=24x-100

For maximum or minimum value, V'=0

12x²-100x+15=0

Apply quadratic formula x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}, here a=12, b= -100 and c=15

x=\frac{-(-100)\pm\sqrt{(-100)^2-4.12.15}}{2.12}

\Rightarrow x=\frac{100\pm\sqrt{9280}}{2.12}

\Rightarrow x=0.1528,8.18

For x= 8.18, The value of (15-2x) and (10-2x) will negative.

∴x=0.1528 .

Now, V''|_{x=0.1528}=24(0.1528)-100

∴At x=0.1528 inch, the volume of the metal box will be maximum.

Therefore the dimensions of the square should be 0.1528 inch by 0.1528 inch so, the box  has largest volume.

4 0
3 years ago
Factorise fully 6x^2 - 15x
Ksivusya [100]

Answer:

The answer is :

3x(2x-5)

7 0
2 years ago
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