1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
snow_lady [41]
2 years ago
10

Which equation is a direct variation function? y=x y=1/4x+2 y=x2 y=4​

Mathematics
1 answer:
AveGali [126]2 years ago
3 0

Answer:

y=x

Step-by-step explanation:

The equation which is a direct variation function is

Y=X

You might be interested in
Classify each pair of angels listed below as adjacent or vertical.
Stolb23 [73]

Answer:

ntersecting lines DA and CE.

To find:

Each pair of adjacent angles and vertical angles.

Solution:

Adjacent angles are in the same straight line.

Pair of adjacent angles:

(1) ∠EBD and ∠DBC

(2) ∠DBC and ∠CBA

(3) ∠CBA and ∠ABE

(4) ∠ABE and ∠EBD

Vertical angles are opposite angles in the same vertex.

Pair of vertical angles:

(1) ∠EBD and ∠CBA

(2) ∠DBC and ∠EBA

5 0
3 years ago
Rewrite the following linear equation in slope-intercept form. y+4=-2(x-1)
romanna [79]

Answer:

y = -2x - 1

Step-by-step explanation:

Rewrite y + 7 = -2(x - 3) in slope-intercept form (which is y = mx + b):

First, perform the indicated multiplication:

y + 7 = -2x + 6

Combining the constants, we get

y = -2x - 1

This is the desired equation in slope-intercept form.  slope is -2 and y-intercept is -1.

5 0
3 years ago
A rectangle is placed around a semicircle as shown below. The length of the rectangle is 14mm. Find the area of the shaded regio
Damm [24]

Image is missing, so i have attached it

Answer:

21.07 mm²

Step-by-step explanation:

We will use the Formulas:

Area of semicircle = πr²/2

Area_rectangle = Length x width = Lw

We are given:

Length of rectangle = 14 mm

From the attached image, the diameter of the semicircle is equal to the length of the rectangle.

Thus;

diameter of semicircle = length of rectangle

Therefore,

diameter of semicircle = 14 mm

Also, from the attached image, the radius of the semicircle is equal to the width of the rectangle.

Thus;

diameter of semicircle/2 = radius of semicircle

Hence;

radius of semicircle = 14/2 = 7mm = width of rectangle

Thus;

Area of rectangle = L*w = 14 × 7 = 98 mm²

Area of semicircle = πr²/2 = π×7²/2 = 76.93 mm²

To get the area of the shaded region, we will subtract area of the semi-circle from the area of the rectangle.

Area of shaded region = Area_rectangle - Area_semicircle = 98 - 76.93 = 21.07 mm²

7 0
3 years ago
F(x) = 5(x + 1)(x - 1)
Mamont248 [21]
Standard From =
F(x) = 5x2 - 5
6 0
3 years ago
In a recent poll 60% of the middle school preferred pizza for lunch on Friday 27% prefer tacos and 13% preferred hotdogs the mid
serious [3.7K]

Answer:

516 students preferred pizza

Step-by-step explanation:

To solve this problem we have to calculate 60% of the total students (860)

To get the percentage of a number we have to divide by 100 and then multiply by the number it indicates, in this case 60

860 %60 = 860 / 100 * 60

860 / 100 * 60 =

8.6 * 60 = 516

60% of 860 is 516

this means that for Friday lunches 516 students preferred pizza

5 0
3 years ago
Other questions:
  • Helppp i dont understand this
    12·2 answers
  • What is the system of equations for -3x+2y=56 and -5x - 2y = 24
    14·1 answer
  • PLEASE HELP ME NOW!!!!!!!!!
    8·1 answer
  • The graph of which function has a minimum located at (4, –3)?
    10·2 answers
  • How would I go about solving this?
    9·1 answer
  • Find the center-radius form of the equation of the circle described. Then graph the circle. Center (0,0), radius 8
    7·1 answer
  • What is the arc length of arc CD in the circle below?
    5·2 answers
  • Please answer this correctly
    14·1 answer
  • Which point is located at (2, 3)?<br><br><br><br><br> A<br> B<br> C<br> Or<br> D
    5·1 answer
  • Find the measure of each angle.
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!