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Andrej [43]
2 years ago
10

What is the mean of the normal distribution shown below?

Mathematics
2 answers:
Butoxors [25]2 years ago
5 0
5 is the answer only 5
maks197457 [2]2 years ago
4 0

Answer:5

Step-by-step explanation: the middle is 2 and 3 so since there is 2 numbers add them and you get 5.

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Please help. will mark brainliest
Semmy [17]

DH = HF      

x + 1 = 3y         

y = (x + 1) ⁄ 3        


GH = HE

 3x – 4 = 5y + 1 

 y = (3x – 5) ⁄ 5 

            

 y = y 

 (x + 1) ⁄ 3 = (3x – 5) ⁄ 5 

5x + 5 = 9x – 15 

4x = 20 

 x = 5 


y = (x + 1) ⁄ 3        

y = (5 + 1) ⁄ 3       

y = 2 





4 0
3 years ago
Please help me with #'s 5&6
Fynjy0 [20]

5.\\(x+3)^2+7=-2\qquad|-7\\\\(x+3)^2=-9 < 0\\\\\text{NO REAL SOLUTION}\\\\(x+3)^2=-9\to x+3=\pm\sqrt{-9}\\\\x+3=-3i\ \vee\ x+3=3i\qquad|-3\\\\\boxed{x=-3-3i\ \vee\ x=-3+3i}

6.\\4(x-10)^2=25\qquad|:4\\\\(x-10)^2=\dfrac{25}{4}\to x-10=\pm\sqrt{\dfrac{25}{4}}\\\\x-10=-\dfrac{\sqrt{25}}{\sqrt4}\ \vee\ x-10=\dfrac{\sqrt{25}}{\sqrt4}\\\\x-10=-\dfrac{5}{2}\ \vee\ x-10=\dfrac{5}{2}\\\\x-10=-2.5\ \vee\ x-10=2.5\qquad|+10\\\\\boxed{x=7.5\ \vee\ x=12.5}

7 0
3 years ago
Suppose the roots of the polynomial $x^2 - mx + n$ are positive prime integers (not necessarily distinct). Given that $m &lt; 20
Vsevolod [243]

Answer:

<em>18</em> values for n are possible.

Step-by-step explanation:

Given the quadratic polynomial:

$x^2 - mx + n$

such that:

Roots are positive prime integers and

$m < 20$

To find:

How many possible values of n are there ?

Solution:

First of all, let us have a look at the sum and product of a quadratic equation.

If the quadratic equation is:

Ax^{2} +Bx+C

and the roots are: \alpha and \beta

Then sum of roots, \alpha+\beta = -\frac{B}{A}

Product of roots, \alpha \beta = \frac{C}{A}

Comparing the given equation with standard equation, we get:

A = 1, B = -m and C = n

Sum of roots,  \alpha+\beta = -\frac{-m}{1} = m

Product of roots, \alpha \beta = \frac{n}{1} = n

We are given that m  

\alpha and \beta are positive prime integers such that their sum is less than 20.

Let us have a look at some of the positive prime integers:

2, 3, 5, 7, 11, 13, 17, 23, 29, .....

Now, we have to choose two such prime integers from above list such that their sum is less than 20 and the roots can be repetitive as well.

So, possible combinations and possible value of n (= \alpha \times \beta) are:

1.\ 2,  2\Rightarrow  n = 2\times 2 = 4\\2.\ 2, 3 \Rightarrow  n = 6\\3.\ 2, 5 \Rightarrow  n = 10\\4.\ 2,  7\Rightarrow  n = 14\\5.\ 2, 11 \Rightarrow  n = 22\\6.\ 2, 13 \Rightarrow  n = 26\\7.\ 2, 17 \Rightarrow  n = 34\\8.\ 3,  3\Rightarrow  n = 3\times 3 = 9\\9.\ 3, 5 \Rightarrow  n = 15\\10.\ 3, 7 \Rightarrow  n = 21\\

11.\ 3,  11\Rightarrow  n = 33\\12.\ 3, 13 \Rightarrow  n = 39\\13.\ 5, 5 \Rightarrow  n = 25\\14.\ 5, 7 \Rightarrow  n = 35\\15.\ 5, 11 \Rightarrow  n = 55\\16.\ 5, 13 \Rightarrow  n = 65\\17.\ 7, 7 \Rightarrow  n = 49\\18.\ 7, 11 \Rightarrow  n = 77

So,as shown above <em>18 values for n are possible.</em>

3 0
3 years ago
F (x) = – x2 + 4x + 1
lora16 [44]

Answer:

x = 0 or x = 3

Step-by-step explanation:

if f(x) = g(x) then – x2 + 4x + 1 = x + 1

add the like terms

-x^2 +3x = 0

-x (x-3) = 0 then x is either 0 or 3

6 0
3 years ago
Read 2 more answers
How does tan 135 degrees compare to tan -135 degrees
Anna007 [38]
Evaluating the tangent function for the two values we obtain the following:
tan 135=tan(135+180)=tan 315=-1

next:
tan -135=tan(180-135)=tan 45=1
thus comparing the two we see that tan 135 is negative while tan -135 is positive
3 0
3 years ago
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