10x-61/12 is the difference of (7x-) - (-3x +
).
An expression is combination of variables, numbers and operators.
The given expression is (7x-) - (-3x +
)
7x-+3x-
7x-20/3+3x-19/4
Add the variable terms and constant terms.
10x-20/3-19/4
The LCM of 3 and 4 is 12/
10x-4-57/12
10x-61/12
Hence, 10x-61/12 is the difference of (7x-) - (-3x +
).
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Answer:
The correct option is D. Discontinuity at (1, 7), zero at (negative four thirds, 0)
Step-by-step explanation:
To find the point of discontinuity :
Put the denominator equal to 0
⇒ x - 1 = 0
⇒ x = 1
Also, if the factor (x - 1) gets cancel, then it becomes a hole rather than a asymptote , ⇒ y = 3x + 4 at x = 1
⇒ y = 7
So, Point of discontinuity : (1, 7)
And the zero is : after cancelling the factor (x - 1) put the remaining factor = 0
⇒ 3x + 4 = 0
⇒ 3x = -4
⇒ x = negative four thirds ( zero of the function)
Therefore, The correct option is D. Discontinuity at (1, 7), zero at (negative four thirds, 0)
The explicit rule for given sequence is:
Further explanation:
We have to determine first of all if the sequence is arithmetic or geometric.
Given sequence is:
12,22,32,42
The common difference is 10 which is same for all consecutive terms. So the sequence is an arithmetic sequence.
The general formula for arithmetic sequence is:
Putting the values of a1 and d
The explicit rule for given sequence is:
Keywords: Arithmetic sequence, Common Difference
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