Now , For 12n to end with 0, it should have 2 as well as 5 in its Prime factors to end with 0, Also to end with 5 , it requires at least a single multiple of 5 in its Prime Factors, So 12n cannot end with the digit 0 or 5.
Answer:
The answer is below
Step-by-step explanation:
Let S denote syntax errors and L denote logic errors.
Given that P(S) = 36% = 0.36, P(L) = 47% = 0.47, P(S ∪ L) = 56% = 0.56
a) The probability a program contains both error types = P(S ∩ L)
The probability that the programs contains only syntax error = P(S ∩ L') = P(S ∪ L) - P(L) = 56% - 47% = 9%
The probability that the programs contains only logic error = P(S' ∩ L) = P(S ∪ L) - P(S) = 56% - 36% = 20%
P(S ∩ L) = P(S ∪ L) - [P(S ∩ L') + P(S' ∩ L)] =56% - (9% + 20%) = 56% - 29% = 27%
b) Probability a program contains neither error type= P(S ∪ L)' = 1 - P(S ∪ L) = 1 - 0.56 = 0.44
c) The probability a program has logic errors, but not syntax errors = P(S' ∩ L) = P(S ∪ L) - P(S) = 56% - 36% = 20%
d) The probability a program either has no syntax errors or has no logic errors = P(S ∪ L)' = 1 - P(S ∪ L) = 1 - 0.56 = 0.44
Answer:
12
Step-by-step explanation:
The computation of the size of the customers is shown below:
Here we find the greatest common divisor of the given numbers
96, 60, 84 ÷ 2
48, 30, 42 ÷ 2
24, 15, 21 ÷ 2
12, 15, 21 ÷ 2
6, 15, 21 ÷ 2
3, 15, 21 ÷ 3
1, 5, 7 ÷ 5
1, 1, 7 ÷ 7
1, 1, 1
By this there are three numbers i.e. 2, 2 and 3
So, the lease common denominator is
= 2 × 2 × 3
= 12
Answer:?
I have no idea sir sorry yt ;-;
Step-by-step explanation:
