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kolbaska11 [484]
3 years ago
10

May has 31 days. How would the experimental probability be affected if someone mistakenly used 30 days to calculate the experime

ntal probability that the maximum temperature will not be greater than 90ºF on a given day in May? (Hint: Select the correct reason with the correct calculation.)
answer choices:
20/31 is greater than 19/30 so using fewer days in the month produces a smaller probability

19/31 is greater than 19/30 so using fewer days in the month produces a smaller probability

20/31 is greater than 19/30 so using fewer days in the month produces a greater probability

19/30 is greater than 20/31 so using fewer days in the month produces a greater probability
Mathematics
1 answer:
Mars2501 [29]3 years ago
3 0
<span>20/31 is greater than 19/30 so using fewer days in the month produces a greater probability i think so 
</span>

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I believe the answer would be (1) because they are not directly related
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Jenny's aquarium holds 25 quarts of water. She buys a new one that holds 32 quarts.
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5 0
2 years ago
Solve for x in the equation x2 - 4x-9 = 29.
erastova [34]

Answer:

x=2+\sqrt{21}\\\\x=2-\sqrt{21}

Step-by-step explanation:

One is given the following equation;

x^2-4x-9=29

The problem asks one to find the roots of the equation. The roots of a quadratic equation are the (x-coordinate) of the points where the graph of the equation intersects the x-axis. In essence, the zeros of the equation, these values can be found using the quadratic formula. In order to do this, one has to ensure that one side of the equation is solved for (0) and in standard form. This can be done with inverse operations;

x^2-4x-9=29

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This equation is now in standard form. The standard form of a quadratic equation complies with the following format;

ax^2+bx+c

The quadratic formula uses the coefficients of the quadratic equation to find the zeros this equation is as follows,

\frac{-b(+-)\sqrt{b^2-4ac}}{2a}

Substitute the coefficients of the given equation in and solve for the roots;

\frac{-(-4)(+-)\sqrt{(-4)^2-4(1)(-38)}}{2(1)}

Simplify,

\frac{-(-4)(+-)\sqrt{(-4)^2-4(1)(-38)}}{2(1)}\\\\=\frac{4(+-)\sqrt{16+152}}{2}\\\\=\frac{4(+-)\sqrt{168}}{2}\\\\=\frac{4(+-)2\sqrt{21}}{2}\\\\=2(+-)\sqrt{21}

Therefore, the following statement can be made;

x=2+\sqrt{21}\\\\x=2-\sqrt{21}

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Where do two perpendicular lines intersect
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3 years ago
Read 2 more answers
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The square of 4 and 2 adds up to 20!
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3 years ago
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