Answer: 3^15
Step-by-step explanation:
Explained in attached picture. Hope you'll find it easy to understand. If not, you can comment :)
Answer:
The minimum sample size required to create the specified confidence interval is 2229.
Step-by-step explanation:
We have that to find our
level, that is the subtraction of 1 by the confidence interval divided by 2. So:

Now, we have to find z in the Ztable as such z has a pvalue of
.
So it is z with a pvalue of
, so 
Now, find the margin of error M as such

In which
is the standard deviation of the population and n is the size of the sample.
What is the minimum sample size required to create the specified confidence interval
This is n when 





Rounding up
The minimum sample size required to create the specified confidence interval is 2229.
This is a binomial distribution.
p = 0.71, q = 1 - p = 1 - 0.71 = 0.29, n = 20
P(x ≤ 19) =1 - P(x = 20) = 1- 20C20 x (0.71)^(20 - 20) x (0.29)^20 = 1 - 0.29^20 = 1 - 0 = 1
Answer:
see attached
Step-by-step explanation:
Based on 100 trials, we don't expect the experimental probability to deviate much from the theoretical probability. The scales on the attached graphs are hard to read, but you want to choose the graph that ...
- has bars that total 100 in their length
- has bars that are approximately .50, .25, .17, .08 in height, corresponding to the area fraction
We think the appropriate choice may be C, but we cannot tell for sure.
Answer:
4296 kg
Step-by-step explanation:
40/100 = x/7160
716 times 6 is 4296