Consider two hypothetical genes, Aand B.A codes for the trait plant pigment where aa individuals lack all pigment. Gene B codes
for bent leaf trait where bb individuals have bent leaves. In the following cross between a heterozygotewith normal plant pigment and straight leavesand homozygousrecessive with no pigment and bent leaves what phenotypic ratios would be attained in the following situations. (A) AaBb x aabb a. The A and B genes are on separate chromosomes
(B) The A and B genes are on the same chromosomes, but are so close that recombination never occurs between A and B.
(C) The A and B genes are on the same chromosomes, but are so far apart that recombination always occurs between A and B.
(D) The A and B genes are linked on the same chromosomes 10 map units apart.
(E) The A and B genes are linked on the same chromosomes 5 map units apart.
In the above question the ratio of phenotype is asked but the options given aren't according to phenotype hence the options need correction.
But, if you consider the ratio of genotype then option ( A= AaBb x aabb a. The A and B genes are on separate chromosomes ) would be the correct answer.
Reading through the entire investigation before beginning the procedure can help prevent accidents by giving you the knowledge of what to do beforehand and preparing you for what is to come.
