Lara wrote the following statement:

Mathematics

2 answers:

Viktor [21]3 years ago

7 0

Answer: C. Lara is incorrect, because more than one triangle can be drawn with the given information

Step-by-step explanation:

An isosceles triangle is a triangle which has only one pair of equal sides or equal angles.

Since, If one angle of isosceles triangle is 75°,

Then there are two possible cases,

Case 1: The angles of the triangles are 75°, 75° and 30°.

Case 2: The angles of the triangle are 75°, 52.5° and 52.5°.

Hence, she is incorrect because more than one triangle can be possible by the given information.

⇒ Option C is correct.

trapecia [35]3 years ago

4 0

<span>C. Lara is incorrect, because more than one triangle can be drawn with the given information.</span>

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So, I need to find the Mean Median Mode and Range with this frequency table, and I have no idea how to do that. Can somebody ple

olya-2409 [2.1K]

Mean: average of the numbers. Add them up, divide by how many numbers/entries there are.
-2 + -1 + 0 + 0 + 0 + 0 + 2 + 4 = 3
3 divided by 8 = 0.375
Your mean is 0.375

Median: write the data in numerical order, find the middle number.

-2, -1, 0, 0, 0, 0, 2, 4
In this data set, there are an even number of entries, so we average the middle two numbers. Thankfully, here, the middle two are the same, so your median is 0.

Mode: the number that appears the most often in the data set

Your mode is also 0, because there are more zeroes than any other number in the data set.

Range: the distance on a number line between the highest and lowest number.

The distance between -2 and 4 is 6.4 - (-2) = 6

Please LMK if you have questions

8 0

3 years ago

Which is the approximate solution to the system y = 0.5x + 3.5 and y = − 2/3 x + 1/3 shown on the graph? (–2.7, 2.1) (–2.1, 2.7)

AlekseyPX

Answer:

The approximate solution to the system is $(-2.7, 2.1)$ .

Step-by-step explanation:

To solve the system of equations $\begin{bmatrix}y=0.5x+3.5\\ y=-\frac{2}{3}x+\frac{1}{3}\end{bmatrix}$ you must:

$\mathrm{Rationalize\:equations}\\\\\begin{bmatrix}y=\left(\frac{1}{2}\right)x+\left(\frac{7}{2}\right)\\ y=-\frac{2}{3}x+\frac{1}{3}\end{bmatrix}$

$\mathrm{Subsititute\:}y=-\frac{2}{3}x+\frac{1}{3}\\\\\begin{bmatrix}-\frac{2}{3}x+\frac{1}{3}=\frac{1}{2}x+\frac{7}{2}\end{bmatrix}$

$\mathrm{Isolate}\:x\:\mathrm{for}\:-\frac{2}{3}x+\frac{1}{3}=\frac{1}{2}x+\frac{7}{2}\\\\-\frac{2}{3}x=\frac{19}{6}+\frac{1}{2}x\\\\-\frac{7}{6}x=\frac{19}{6}\\\\6\left(-\frac{7}{6}x\right)=\frac{19\cdot \:6}{6}\\\\-7x=19\\\\x=-\frac{19}{7}\approx-2.7$

$\mathrm{For\:}y=-\frac{2}{3}x+\frac{1}{3}\\\\\mathrm{Subsititute\:}x=-\frac{19}{7}\\\\y=-\frac{2}{3}\left(-\frac{19}{7}\right)+\frac{1}{3}\\\\y=\frac{15}{7}\approx 2.1$