<u>Answer:</u>
Probability of getting three jacks = 
<u>Step-by-step explanation:</u>
It is given that you deal three cards from a regular deck which contains 52 cards.
We are to find the probability of getting all three Jack cards.
We know that there are a total of 4 jacks in a regular deck of 52 cards.
Therefore, the probability of getting three jacks =
X= 130°
Step-by-step explanation:
From E, draw EF || AB || CD.
Now, EF || CD and CE is the transversal.
So; <DCE + <CEF = 180° [co. int. <s]
x° + <CEF = 180°
<CEF = (180° – x°).
Again, EF || AB and AE is the transversal.
So; <BAE + <AEF = 180° 01 [co. int. <s ]
105° + <AEC+ <CEF = 180°
105° +25° + (180° – x°) = 180°
x° = 130°
I hope I helped you^_^
Answer:
Step-by-step explanation:
The input-output table can be made by putting value of x and finding the value of f(x)
f(x) = 3x^2-x+4
f(0) = 3(0)^2-0+4 = 0-0+4 = 4
f(1) = 3(1)^2-1+4 = 3-1+4 = 2+4 =6
f(2) = 3(2)^2-2+4 = 3(4)-2+4 = 12-2+4 = 10+4 = 14
f(3) = 3(3)^2-3+4 = 3(9)-3+4 = 27-3+4 = 24+4 = 28
So put value of x and find f(x) and fill the input-output table.
x f(x)
0 4
1 6
2 14
3 28
Plug in x into the equation. Take x= -2 for example. Your equation is 2x-5, so instead of x, you put -2.
2(-2)-5 = -9
Your table is as follows:
(-2,-9)
(-1,-7)
(0,-5)
(1,-3)
Answer:
20%=3800 => all of it is 19000
i didn't undrestand what do you want
sorry:)
