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Feliz [49]
3 years ago
14

Tell whether the lines through the given points are parallel, perpendicular, or neither.

Mathematics
1 answer:
Nataly_w [17]3 years ago
5 0

Step-by-step explanation:

The slope of a line connecting two points is:

m = (y₂ − y₁) / (x₂ − x₁)

The slope of line 1 is:

m = (4 − 0) / (7 − 1)

m = 2/3

The slope of line 2 is:

m = (6 − 0) / (3 − 7)

m = -3/2

Parallel lines have equal slopes.

Perpendicular lines have opposite inverse slopes.

2/3 and -3/2 are opposite inverses, so the lines are perpendicular.

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Step-by-step explanation:

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2 years ago
What is the solution to this equation -13x=52​
Tom [10]

Answer:

-4

Step-by-step explanation:

You multiply -13*-4=52

8 0
3 years ago
What is an equation in point-slope form of the line that
-Dominant- [34]

Step-by-step explanation:

To find an equation of a line in point slope form when given the slope and a point we use the formula

y -  y_1 = m(x -  x_1)

where

m is the slope

( x1 , y1) is the point

From the question the point is (-3, -1) and slope 2

The equation is

<h2>y + 1 = 2(x + 3)</h2>

Hope this helps you

5 0
2 years ago
Jer saw 91 squirrels and 1⁄3 as many chipmunks. Which of the following is a good estimation of how many more squirrels he saw th
boyakko [2]
60 more squirrels is the answer because sine its an estimate, 91 turns into 90
therefore u have 
90 squirrels and 1/3 as many chipmunks
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90 - 30 = 60
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8 0
3 years ago
In a flight of 600 km, the speed of the aircraft was slowed down due to bad weather. The average speed of the trip was decreased
UkoKoshka [18]

The average speed would be 600 km/hr.

Step-by-step explanation:

Let the original speed be 'x'

Let the decreased speed be 'x-200'

Distance = 600 km

Time increased by 30 minutes

According to question, it becomes,

\dfrac{600}{x-200}-\dfrac{600}{x}=\dfrac{30}{60}\\\\\dfrac{x-(x-200)}{x^2-200x}=\dfrac{1}{2\times 600}\\\\\dfrac{200}{x^2-200x}=\dfrac{1}{1200}\\\\240000=x^2-200x\\\\x^2-200x-240000=0\\\\x=600,-400

So, The average speed would be 600 km/hr.

5 0
3 years ago
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