Answer: fourth option
Explanation:1) the pair x = 3 f(x) = 0, leads you to probe this:
f(3) = 0 = A [4 ^ (3 - 1) ] + C = 0
=> A [4^2] = - C
A[16] = - C
if A = 1/4
16 / 4 = 4 => C = - 4
That leads you to the function f(x) = [1/4] 4 ^( x - 1) - 4
2) Now you verify the images for that function for all the x-values of the table:
x = 2 => f(2) + [1/4] 4 ^ (2 - 1) - 4 = [1/4] 4 - 4 = 4 / 4 - 4 = 1 - 4 = - 3 => check
x = 3 => f(3) = [1/4] 4^ (3 - 1) - 4 = [1/4] 4^2 - 4 = 16 / 4 - 4 = 4 - 4 = 0 => check
x = 4 -> f(4) = [1/4] 4^ (4-1) - 4 = [1/4] 4^(3) - 4 = (4^3) / 4 - 4 = 4^2 - 4 = 16 - 4 = 12 => check.
Therefore, you have proved that the answer is the fourth option.
Answer:
BBC News is a British free-to-air television news channel ;)
Step-by-step explanation:
It was launched as BBC News 24 on 9 November 1997 at 5:30 pm as part of the BBC's foray into digital domestic television channels, becoming the first competitor to Sky News, which had been running since 1989.
To answer this question, we need to find the winning probability in either case.
Probability = no. of outcomes / total no. of possible outcomes
<u>When Hope pulled her defender :</u>
Total no. of games = 9
No. of games won = 3
Winning probability = 3/9 =1/3
<u>When Hope left her defender :</u>
Total no. of games = 10
No. of games won = 6
Winning probability = 6/10 = 3/5
We know that , 1/3 < 3/5.
So, Hope should not pull her defender, as the winning probability is better when Hope left her defender.
Answer : A. Hope should not pull her defender.
Step-by-step explanation:
these are multiplications.
you could also write
4 + 5×(p - 1)
now, we need to calculate the contents of brackets (if we can), then do the multiplications and divisions, before we can do the then remaining additions and subtractions.
if we cannot do a calculation directly (because there is a variable involved), we need to do and document the single steps for the individual parts involved.
so,
4 + 5×(p - 1) = 4 + 5×p + 5×-1 = 4 + 5p - 5 = 5p - 1
remember, a multiplication of 2 expressions is done by multiplying every term of one expression with every term of the other expression and adding the results up (by considering their individual signs, of course).