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3 years ago

Anyone know the answer?? ( I got confused half way)

Mathematics

2 answers:

Liula [17]3 years ago

8 0

Yes the answer is eight and three forths

weqwewe [10]3 years ago

7 0

The answer is 8 and 3 fourths which would be written as 8 3/4

You might be interested in

Multiply and combine like terms: -5x – 4(9 – 2x)

Alex777 [14]

-5x-36+8x

3x-36

3(x-18)

3 0

2 years ago

A candy company claims that 25% of the candies in its bags are colored green. Steve buys 32 bags of 32 candies, randomly selects

Luden [163]

Answer:

45.88%

Step-by-step explanation:

We have in this case a binomial distribution when p = 0.25, since the probability is 25%

. The formula that we will use in excel is BINOM.DIST, separated by commas we must put the value of x, n, p and also if it is true or false. We know that n equals 32.

In this case we need to know when x = 7, 8 and 9 and add this, and thus we will obtain the probability:

P (X = 7) + P (X = 8) + P (X = 9)

Excel formulas: = BINOM.DIST (7,32,0.25, FALSE) + BINOM.DIST (8,32,0.25, FALSE) + BINOM.DIST (9,32,0.25, FALSE)

P = 0.1546 + 0.1610 + 0.1431

P = 0.4588

Probability that steve agrees with the company's claim 45.88%

4 0

3 years ago

Asap! super urgent! help me outtt :'(

mrs_skeptik [129]

Answer:

3/47

Step-by-step explanation:

of the 47 total cars, 3 of them are a beige SUV

8 0

3 years ago

Read 2 more answers

5. In the figure, . Solve for . Show your work.

natima [27]

Answer:

Step-by-step explanation:

6/10=9/x

cross multiply

6x=9*10

6x=90

x=90/6x=15

3 0

3 years ago

An article contained the following observations on degree of polymerization for paper specimens for which viscosity times concen

devlian [24]

Answer:

(a) A 95% confidence interval for the population mean is [433.36 , 448.64].

(b) A 95% upper confidence bound for the population mean is 448.64.

Step-by-step explanation:

We are given that article contained the following observations on degrees of polymerization for paper specimens for which viscosity times concentration fell in a certain middle range:

420, 425, 427, 427, 432, 433, 434, 437, 439, 446, 447, 448, 453, 454, 465, 469.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean = $\frac{\sum X}{n}$ = 441

s = sample standard deviation = $\sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }$ = 14.34

n = sample size = 16

$\mu$ = population mean

Here for constructing a 95% confidence interval we have used One-sample t-test statistics as we don't know about population standard deviation.

So, 95% confidence interval for the population mean, $\mu$ is ;

P(-2.131 < $t_1_5$ < 2.131) = 0.95 {As the critical value of t at 15 degrees of

freedom are -2.131 & 2.131 with P = 2.5%}

P(-2.131 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 2.131) = 0.95

P( $-2.131 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $2.131 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

P( $\bar X-2.131 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+2.131 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

95% confidence interval for $\mu$ = [ $\bar X -2.131 \times {\frac{s}{\sqrt{n} } }$ , $\bar X +2.131 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $441-2.131 \times {\frac{14.34}{\sqrt{16} } }$ , $441+2.131 \times {\frac{14.34}{\sqrt{16} } }$ ]

= [433.36 , 448.64]

(a) Therefore, a 95% confidence interval for the population mean is [433.36 , 448.64].

The interpretation of the above interval is that we are 95% confident that the population mean will lie between 433.36 and 448.64.

(b) A 95% upper confidence bound for the population mean is 448.64 which means that we are 95% confident that the population mean will not be more than 448.64.

6 0

3 years ago