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3 years ago

Kitty has a vegetable garden that measures 16.75 feet in length and 5.8 feet in width. Find the area of the garden

Mathematics

2 answers:

vladimir2022 [97]3 years ago

8 0

Area= length x width
A= 16.75 x 5.8 = 97.15 ft^2

Agata [3.3K]3 years ago

6 0

97.15 is the area. All I did is multiply both numbers.

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Scores on a test are normally distributed with a mean of 81.2 and a standard deviation of 3.6. What is the probability of a rand

Misha Larkins [42]

Answer:

The probability of a randomly selected student scoring in between 77.6 and 88.4 is 0.8185.

Solution:

Given, Scores on a test are normally distributed with a mean of 81.2

And a standard deviation of 3.6.

We have to find What is the probability of a randomly selected student scoring between 77.6 and 88.4?

For that we are going to subtract probability of getting more than 88.4 from probability of getting more than 77.6

Now probability of getting more than 88.4 = 1 - area of z – score of 88.4

$\mathrm{Now}, \mathrm{z}-\mathrm{score}=\frac{88.4-\mathrm{mean}}{\text {standard deviation}}=\frac{88.4-81.2}{3.6}=\frac{7.2}{3.6}=2$

So, probability of getting more than 88.4 = 1 – area of z- score(2)

= 1 – 0.9772 [using z table values]

= 0.0228.

Now probability of getting more than 77.6 = 1 - area of z – score of 77.6

$\mathrm{Now}, \mathrm{z}-\text { score }=\frac{77.6-\text { mean }}{\text { standard deviation }}=\frac{77.6-81.2}{3.6}=\frac{-3.6}{3.6}=-1$

So, probability of getting more than 77.6 = 1 – area of z- score(-1)

= 1 – 0.1587 [Using z table values]

= 0.8413

Now, probability of getting in between 77.6 and 88.4 = 0.8413 – 0.0228 = 0.8185

Hence, the probability of a randomly selected student getting in between 77.6 and 88.4 is 0.8185.

4 0

3 years ago

Please help 30 points Asap

Andrej [43]

40 units2˛

Looking at the figure, the rectangle has the vertexes (2,1), (3,-3), (-5,-5) and (-6,-1). The parallelogram has the vertexes (2,7), (3,3), (3,-3), and (2,1).

The area of a parallelogram is base times height. We have 2 vertical lines at x=2 and x=3, so the height is 1. And the length of the line from (3,3) to (3,-3) is 6, so the base is 6. Therefore the area of the parallelogram is 1*6 = 6.

The rectangle is a tad trickier since it's not aligned with either the x or y axis. But we can use the Pythagorean theorem to get the lengths.

L = sqrt((2 - -6)^2 + (1 - -1)^2)

L = sqrt(8^2 + 2^2)

L = sqrt(64 + 4)

L = sqrt(68) = 2*sqrt(17)

W = sqrt((2-3)^2 + (1- -3)^2)

W = sqrt((-1)^2 + 4^2)

W = sqrt(1 + 16)

W = sqrt(17)

And the area is length * width, so:

2*sqrt(17)*sqrt(17) = 2 * 17 = 34

And the total area is the sum of the areas, so

34 + 6 = 40

So the area of the figure is 40 square units.

7 0

3 years ago

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8-6x=-28 I need help plzzz

Schach [20]

The answer is 6. 8-6(6) = -28.

3 0

3 years ago

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Set X: {51,49,37,28,33,39,49,42} Set Y :{23,2934,36,39,22,25,33}

SpyIntel [72]

Answer:

Step-by-step explanation:

126

8 0

3 years ago

What are the first three terms of the sequence represented by the recursive formula

AnnyKZ [126]

Explecit formula
hmm, seems to be a geometric sequence
so
an=a1+d(n-1)
d=common differnce
a1=first term

given
a1=firstterm=9.2

and the difference between each tierm is 1.8

an=9.1-1.8(n-1) is da equation

so 4th option

5 0

3 years ago