You have $15 and admission is $5, so you know have $10 before doing any games. If you wanted to play 12 games, you would need $10.20, which you do not have. But, if you wanted to play 11 games, then you would need $9.35, which is just under $10.
So the maximum amount of games that you could play would be 11 games.
Answer:
7+28=35
Step-by-step explanation:
a an c are 65 d and b are 25 those are four of them
M+n+3+m+n+4
=3m+2n+7
answer
C. 3m+2n+7
1 = 4 angles
2 = perpendicular
Hope that helped ;)
