3 years ago

For all pairs of real numbers M and V where M = 3V + 6, V = ?

Mathematics

1 answer:

Ede4ka [16]3 years ago

6 0

$M = 3V + 6 \ \ | (-6)\\ \\M-6=3V+6-6 \\ \\M-6 =3V \ \ /:3 \\ \\V=\frac{M }{3}-\frac{6}{3} \\ \\V=\frac{M}{3 }- 2$

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· Amanda has $210 in her school lunch account. She spends $35 each week on school lunches. The

tigry1 [53]

Answer:

(See step-by-step)

Step-by-step explanation:

Let’s start by making A-(X) and W-(Y). So, when substituting the variables you get x=210-35y. When x=0, the answer to the equation is 6. So, the y-intercept (when x=0) is 6 or (0,6). When y=0, the answer to the equation/x-intercept(y=0) is 210 or (210,0). The graph itself looks like the image included.

The domain, realistically, is x>=0 however on the graph itself, the domain is x= All Real Numbers. The range realistically is y>=0, but on the graph it is also All Real Numbers.

The x-intercept is the account when no weeks have passed and no money is lost (210) and the y-intercept is the maximum amount of weeks before there is no more money in the account (6).