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2 years ago

7 is not an example of A) a variable B) an expression C) a constant D) a term

Mathematics

2 answers:

Varvara68 [4.7K]2 years ago

6 0

Answer:

A) a variable

Step-by-step explanation:

A) a variable a variable changes value 7 does not change

B) an expression does not have an equal sign 7 does not have an equal sign

C) a constant 7 is constant, it does not change

D) a term is a group of numbers and variables with no operators

insens350 [35]2 years ago

6 0

Answer:

7 is not an example of a variable.

Step-by-step explanation:

7 is not an example of a variable. 7 is a constant (C), and could be an expression or a term.

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Rewrite the rational exponent as a radical by extending the properties of integer exponents.

Aloiza [94]

$\bf ~~~~~~~~~~~~\textit{negative exponents} \\\\ a^{-n} \implies \cfrac{1}{a^n} \qquad \qquad \cfrac{1}{a^n}\implies a^{-n} \qquad \qquad a^n\implies \cfrac{1}{a^{-n}} \\\\\\ \textit{also recall that }a^{\frac{ n}{ m}} \implies \sqrt[ m]{a^ n} \qquad \qquad \sqrt[ m]{a^ n}\implies a^{\frac{ n}{ m}} \\\\ -------------------------------$

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3 years ago

Read 2 more answers

Which of the following is the y-intercept of the line whose equation is 7y-42×+7=0?

timama [110]

Answer:

7 is the y intercept

Step-by-step explanation:

5 0

2 years ago

Use theorem 7. 4. 2 to evaluate the given laplace transform. do not evaluate the convolution integral before transforming. (writ

irga5000 [103]

With convolution theorem the equation is proved.

According to the statement

we have given that the equation and we have to evaluate with the convolution theorem.

Then for this purpose, we know that the

A convolution integral is an integral that expresses the amount of overlap of one function as it is shifted over another function.

And the given equation is solved with this given integral.

So, According to this theorem the equation becomes the

$\mathscr{L} \left( \int_{0}^{t} e^{-\tau} \cos \tau d \tau \right) = \frac{ \mathscr{L} (e^{-\tau} \cos \tau ) }{s} \\\mathscr{L} \left( \int_{0}^{t} e^{-\tau} \cos \tau d \tau \right) = \frac{\frac{s+1}{(s+1)^2+1}}{s} \\\mathscr{L} \left( \int_{0}^{t} e^{-\tau} \cos \tau d \tau \right) = \frac{1}{s}\left (\frac{s+1}{(s+1)^2+1} \right).$

Then after solving, it become and with theorem it says that the

$\mathscr{L} \left( \int_{0}^{t} f(\tau) d\tau \right) = \frac{\mathscr{L} ( f(\tau))}{s} .$

Hence by this way the given equation with convolution theorem is proved.

So, With convolution theorem the equation is proved.

Learn more about convolution theorem here

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1 year ago

PLEASE HELP! SUPER STUCK!!!

Anastasy [175]

Answer:

The graphed function is Nonlinear

3 0

2 years ago

the sum of the ages of josh and autumn is 88 years 9 years ago josh was 4 times autumn age how old is josh now

forsale [732]

Let
x---------> <span> josh"age
y--------> </span><span>autumn' age

we know that
x+y=88--------> y=88-x---------> equation 1
(x-9)=4*(y-9)--------> equation 2

substitute equation 1 in equation 2
(x-9)=4*(88-x-9)
x-9=4*(79-x)
x-9=316-4x
x+4x=316+9
5x=325
x=65

the answer is
</span>josh"age is 65 years

3 0

2 years ago