6b-18c+18x is simplified for you
Answer: a. The correlation coefficient of the data is positive.
Step-by-step explanation:
Estimated slope of sample regression line = 
Here , confidence interval : (-0.181, 1.529)
Estimated slope of sample regression line = 
![=\dfrac{1.348}{2}\\\\=0.674\ \ \ \ [\text{ positive}]](https://tex.z-dn.net/?f=%3D%5Cdfrac%7B1.348%7D%7B2%7D%5C%5C%5C%5C%3D0.674%5C%20%5C%20%5C%20%5C%20%5B%5Ctext%7B%20positive%7D%5D)
⇒Correlation coefficient(r) must be positive, So a. is true.
But, d. and e. are wrong(0.674 ≠ 0 or 1.348).
We cannot check residuals or its sum from confidence interval of slope of a regression line, so b is wrong.
We cannot say that scatterplot is linear as we cannot determine it from interval, so c. is wrong
So, the correct option : a. The correlation coefficient of the data is positive.
Both of these conditions must be true in order for the assumption that the binomial distribution is approximately normal. In other words, if
and
then we can use a normal distribution to get a good estimate of the binomial distribution. If either np or nq is smaller than 5, then a normal distribution wouldn't be a good model to use.
side note: q = 1-p is the complement of probability p
Answer:
The Mean Absolute Deviation is 11
Step-by-step explanation:
Given:
325, 310, 289, 288, 285, 285, 285, 280, 280 and 273
Mean = 290
Required:
Calculate the Mean Absolute Deviation
Provided that we have the value of the mean to be 290 from the question; the following steps will calculate the Mean Absolute Deviation
Step 1: Subtract the mean weight from each weight
325 - 290 = 35
310 - 290 = 20
289 - 290 = -1
288 - 290 = -2
285 - 290 = -5
285 - 290 = -5
285 - 290 = -5
280 - 290 = -10
280 - 290 = -10
273 - 290 = -17
Step 2: Calculate the absolute value of the each results above
|35| = 35
|20| = 20
|-1| = 1
|-2| = 2
|-5| = 5
|-5| = 5
|-5| = 5
|-10| = 10
|-10| = 10
|-17| = 17
Step 3: Calculate the mean of the data above
Mean Absolute Value = 
Mean Absolute Value = 
Mean Absolute Value = 11
Hence, the Mean Absolute Deviation is 11