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Juliette [100K]
3 years ago
9

Evaluate 0 ∫ ( 3^3 - 5^2) dx -2

Mathematics
1 answer:
Jobisdone [24]3 years ago
4 0
3^3 = 27
5^2 = 25
27 - 25 = 2

integral of 2 = 2x

(2x) evaluated from -2 to 0
= (0) - (2(-2)) = -(-4) = 4

If you did not make any mistakes in typing your question
the answer would be 4
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5 -2x + 6y= -38<br> ? 3x – 4y = 32<br> •(-4, - 5)<br> •(-5, 4)<br> •(1, – 6)<br> (4, - 5)
Svet_ta [14]

Answer:

Option D (4, -5)

Step-by-step explanation:

This question can be solved by various methods. I will be using the hit and trial method. I will plug in all the options in the both the given equations and see if they  balance simultaneously.

Checking Option 1 by plugging (-4, -5) in the first equation:

-2(-4) + 6(-5) = -38 implies 8 - 30 = -38 (not true).

Checking Option 2 by plugging (-5, 4) in the first equation:

-2(-5) + 6(4) = -38 implies 10 + 24 = -38 (not true).

Checking Option 3 by plugging (1, -6) in the second equation:

3(1) - 4(-6) = 32 implies 3 + 24 = 32 (not true).

Since all the options except Option 4 have been ruled out, therefore, (4,-5) is the correct answer!!!

7 0
3 years ago
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Mashutka [201]
375 because if you do 27x25=675 then I did 675-300=375.
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Can someone please help me
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Answer Is a

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Step-by-step explanation:

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