Question

I need help on number 9. I don’t even know how to start

Answer 1

begin by pulling 2 out of the numerator using the distributive property.

numerator: 2(16x^4 - 25)              and now factor

numerator: 2(4x^2 - 5)(4x^2 + 5)

Now go to the denominator. It looks messy but it will break down.

Pull out 4x^2 for the first two terms and 5 for the last 2 terms. Use the distributive property.

denominator: 4x^2(x - 3) - 5(x - 3)  now x - 3 is the common term.

denominator: (x - 3)(4x^2 - 5)

Put the two results together.

$\dfrac{2(4x^2- 5)*(4x^2+5)}{(4x^2-5)(x-3)}$

After canceling out 4x^2 - 5 on both the numerator and the denominator, you are left with.

$\dfrac{2(4x^2+5)}{(x-3)}$

Answer 2

Here. scientific notations in division form.
i just finished learning that subject. :)