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valentina_108 [34]
3 years ago
9

NEED HELP! [URGENT] Submit the worksheet with your constructions to your teacher to be graded.

Mathematics
1 answer:
Tresset [83]3 years ago
4 0

give me more details. that's a bit confusing

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F(x)=2x+6
Klio2033 [76]

Answer:

Step-by-step explanation:

F(x) = 2x + 6

G(x) = - 5x - 9

product of F and G .....the product is the result of multiplication

(2x + 6)(-5x - 9) =

-10x^2 - 18x - 30x - 54 =

-10x^2 - 48x - 54 <====

6 0
3 years ago
Read 2 more answers
five years ago, sarah's aunt was 4 times older than sarah. if sarah's aunt is 42 years older then sarah, then sarah, how ols is
Nimfa-mama [501]

Answer:

Therefore, Sara’s current age (5 years later) is 19 years old.

Step-by-step explanation:

Let xx be Sara’s age five years ago. Therefore, Sara’s aunt’s age 5 years ago is 4x4x.

The difference in their ages is a constant, no matter how many years have gone by. (Can you see why?)

4x−x=42

3x=42

x=42/3

x=14

14+5=19

Therefore, Sara’s current age (5 years later) is 19 years old.

4 0
2 years ago
PLS AWNSER NOW
sattari [20]

Answer:

600

Step-by-step explanation:

2000/10=200. 200x3=600

4 0
3 years ago
Can someone help me with this question? <br> (2,5) and (10,3) What is the slope and the y-intercept
Paha777 [63]

Answer:

slope is -1/4

y intercept is 11/2

Step-by-step explanation:

the slope is (3-5)/(10-2) = -2/8 = -1/4 (using the slope formula)

the y intercept we can set up an equation, y= mx + b

we already know m, which is -1/4 (the slope), and to find b, we could just plug in one of the points to get

5 = (-1/4)*2+b

solve the equation

b = 11/2

4 0
3 years ago
HighTech Inc. randomly tests its employees about company policies. Last year in the 560 random tests conducted, 26 employees fai
Tanzania [10]

Answer:

The 98% confidence interval for the proportion of applicants that fail the test is (0.025, 0.067).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

560 random tests conducted, 26 employees failed the test. This means that n = 560, \pi = \frac{26}{560} = 0.046

98% confidence level

So \alpha = 0.02, z is the value of Z that has a pvalue of 1 - \frac{0.02}{2} = 0.99, so Z = 2.33.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.046 - 2.33\sqrt{\frac{0.046*0.954}{560}} = 0.025

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.046 + 2.33\sqrt{\frac{0.046*0.954}{560}} = 0.067

The 98% confidence interval for the proportion of applicants that fail the test is (0.025, 0.067).

5 0
4 years ago
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