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Mekhanik [1.2K]
3 years ago
11

Which of the following is the same as 58%?​

Mathematics
1 answer:
Alecsey [184]3 years ago
6 0

Answer:

58%=0.58

Step-by-step explanation:

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Connor bought a pack of 4 notebooks for<br> $8.20. What was the unit price? please explain
Mamont248 [21]

Answer:

$2.05

Step-by-step explanation:

$8/4 notebooks= $2

.20/4=.05

________________

$2.05

3 0
3 years ago
77÷ -11 <br><br> 20 points!!!!!
stepan [7]

Answer:

7 time 11 is 77 so 77 divided by 11 is 7

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Identify the percent of change as an increase or decrease. Then find the percent of change. Round to the nearest tenth of a perc
bazaltina [42]

I'll do the first two problems to get you started. All problems shown will use the same formula.

===========================================

Problem 4

The formula to use is

C = 100*(B-A)/A

where

A = old value

B = new value

C = percent change

In this case, A = 12 and B = 36, so

C = 100*(B-A)/A

C = 100*(36-12)/12

C = 100*(24/12)

C = 100*2

C = 200%

We have a 200% increase. It is an increase because the value of C is positive.

===========================================

Problem 5

Use the same formula as in the previous problem. This time,

A = 75 is the old value

B = 25 is the new value

C = 100*(B-A)/A

C = 100*(25-75)/75

C = 100*(-50/75)

C = 100*(-2/3)

C = -66.6667%

C = -66.7%

The value of C is negative, so we have a percent decrease of roughly 66.7%

8 0
2 years ago
A student takes a driving test until it is passed.
Leya [2.2K]

Answer:

The probability that the test is taken an even number of times is 0.30.

Step-by-step explanation:

The probability that a student passes the driving test at any attempt is,

<em>p</em> = 4/7.

The event of a student passing in any attempt is independent of each other.

The probability that the test is taken an even number of times is:

P (even number of tests) = P (Passing in the 2nd attempt)

                                                  + P (Passing in the 4th attempt)

                                                       + P (Passing in the 6th attempt) ...

If a student passed in the 2nd attempt it implies that he failed in the first.

Then,  P (Passing in the 2nd attempt) = (\frac{3}{7}) \times (\frac{4}{7})

Similarly, P (Passing in the 4th attempt) = (\frac{3}{7})^{3} \times (\frac{4}{7}), since he failed in the first 3 attempts.

And so on.

Compute the probability of an even number of tests as follows:

P (even number of tests) = (\frac{3}{7}) \times (\frac{4}{7})+(\frac{3}{7})^{3} \times (\frac{4}{7})+(\frac{3}{7})^{5} \times (\frac{4}{7})+...

The result follows a Geometric progression for infinite values.

The sum of infinite GP is:

S=\frac{a}{1-r^{2}}

The probability is:

P (even number of tests) = (\frac{3}{7}) \times (\frac{4}{7})+(\frac{3}{7})^{3} \times (\frac{4}{7})+(\frac{3}{7})^{5} \times (\frac{4}{7})+...

                                          =\frac{(\frac{3}{7})(\frac{4}{7} ) }{1-(\frac{3}{7})^{2}}\\=\frac{12}{49}\times\frac{49}{40}\\  =\frac{12}{40}\\ =0.30

Thus, the probability that the test is taken an even number of times is 0.30.

7 0
3 years ago
Somebody help i need to find the value of x and classify the sides and angles
Galina-37 [17]

Answer:

a) x=18

b) 36 (2*18)

c) 54 (3*18)

d) I'm not exactly sure what it's asking for, so I don't know

Step-by-step explanation:

triangle sum theorem means the sum of every triangle is 180 degrees

so we can make this equation: 180 = 90 + 2x + 3x

solve and you get 18.

7 0
3 years ago
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