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3 years ago

WILL MARK BRAINLIEST!!!

Mathematics

1 answer:

Stells [14]3 years ago

5 0

Let y represent the yellow and x the red.
Y= 3x-5 is your equation

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A recent survey of 50 executives who were laid off during a recent recession revealed it took a mean of 26 weeks for them to fin

g100num [7]

Answer: $(24.28,\ 27.72)$

Step-by-step explanation:

Given : Sample size : $n=50$

Sample mean : $\overline{x}=26$

Standard deviation : $\sigma =6.2$

Significance level : $\alpha=1-0.95=0.05$

Critical value : $z_{\alpha/2}=1.96$

Formula to find the confidence interval for population mean :-

$\overline{x}\pm z_{\alpha/2}\dfrac{\sigma}{\sqrt{n}}\\\\=26\pm(1.96)\dfrac{6.2}{\sqrt{50}}\\\\\approx26\pm1.72\\\\=(26-1.72,\ 26+1.72)\\\\=(24.28,\ 27.72)$

Hence, a 95% confidence interval for the population mean = $(24.28,\ 27.72)$

6 0

3 years ago

Use the general solution to solve 5 – 6x = 8x + 17.

Jlenok [28]

<span> 5 – 6x = 8x + 17
</span>⇔ 5 - 17 = 8x + 6x
⇔ -12 = 14x
⇔ x = -6/7

7 0

3 years ago

Read 2 more answers

Ashley flies a drone 2,530 ft in 5 s. At this rate how many miles does the drone fly in a minute? 1 mi = 5280 ft

Klio2033 [76]

Answer:

I think the answer is 5.75 miles.

Step-by-step explanation:

If the drone flies 2,530 ft in 5 seconds, that means that in one minute it flies 30,360 ft. And 30,360 divided by 5,280 is 5.75.

3 0

3 years ago

BET YOU CANT SOLVE THIS ONE......✋

MakcuM [25]

Umm, where's the question?????

4 0

3 years ago

Read 2 more answers

Renee wants to estimate the percentage of people who lease a car. She surveys 150 individuals and finds that 33 lease a car. Fin

Oduvanchick [21]

Answer: $(0.164,\ 0.276)$

Step-by-step explanation:

The confidence interval of population proportion is given by :-

$\hat{p}\pm z_{\alpha/2}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}$

Given : Sample size : $n=150$

The proportion of individuals lease a car : $hat{p}=\dfrac{33}{150}=0.22$

Significance level : $\alpha: 1-0.9=0.1$

Critical value : $z_{\alpha/2}=1.645$

Then, the confidence interval of population proportion is given by :-

$0.22\pm (1.645)\sqrt{\dfrac{0.22(1-0.22)}{150}}\\\\\approx0.22\pm0.056=(0.164,\ 0.276)$

Hence, the confidence interval for the population proportion with a 90% confidence level= $(0.164,\ 0.276)$

5 0

3 years ago