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Sladkaya [172]
3 years ago
9

WILL MARK BRAINLIEST!!!

Mathematics
1 answer:
Stells [14]3 years ago
5 0
Let y represent the yellow and x the red.
Y= 3x-5 is your equation
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Find the domain of the function f(x)=<img src="https://tex.z-dn.net/?f=%5Csqrt%7Bx%5E3-16x%7D" id="TexFormula1" title="\sqrt{x^3
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Answer:

Please check the explanation.

Step-by-step explanation:

Given the function

f\left(x\right)=\sqrt{x^3-16x}

We know that the domain of the function is the set of input or arguments for which the function is real and defined.  

In other words,  

  • Domain refers to all the possible sets of input values on the x-axis.

Now, determine non-negative values for radicals so that we can sort out the domain values for which the function can be defined.

x^3-16x\ge 0

as x³ - 16x ≥ 0

\left(x+4\right)\left(x-4\right)\ge \:0

Thus, identifying the intervals:

-4\le \:x\le \:0\quad \mathrm{or}\quad \:x\ge \:4

Thus,

The domain of the function f(x) is:

x\left(x+4\right)\left(x-4\right)\ge \:0\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:-4\le \:x\le \:0\quad \mathrm{or}\quad \:x\ge \:4\:\\ \:\mathrm{Interval\:Notation:}&\:\left[-4,\:0\right]\cup \:[4,\:\infty \:)\end{bmatrix}

And the Least Value of the domain is -4.

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5470
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