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Natasha2012 [34]
3 years ago
5

According to the survey. there are more Andoroid (A) users than Apple (I) users

Mathematics
1 answer:
timofeeve [1]3 years ago
7 0
<h2>Users tahn apple </h2>

<h2>Hope you get the answer.... ❤️ ❤️ ❤️ ❤️ </h2>
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What is a three digit number thats an odd multiple of three and the product of its digits is 24 and is larger than 15 squared?
Reika [66]
The only way 3 digits can have product 24 is 
1 x 3 x 8 = 241 x 4 x 6 = 242 x 2 x 6 = 242 x 3 x 4 = 24
So the digits comprises of 1,3,8 or 1,4,6, or 2,2,6, or 2,3,4 
To be divisible by 3 the sum of the digits must be divisible by 3.
1+  3+ 8=12, 1+ 4+ 6= 11, 2 +2 + 6=10, 2 +3 + 4=9Of those sums of digits, only 12 and 9 are divisible by 3. 

So we have ruled out all but integers whose digits consist of1,3,8, and 2,3,4.

Meanwhile they must be odd they either must end in 1 or 3.
The only ones which can end in 1 are 381 and 831.

The others must end in 3. 

They must be greater than 152 which is 225. So the

First digit cannot be 1. So the only way its digits can contain of1,3,8 and close in 3 is to be 813.

The rest must contain of the digits 2,3,4, and the only way they can end in 3 is to be 243 or 423.  
So there are precisely five such three-digit integers: 381, 831, 813, 243, and 423.
7 0
3 years ago
Vineet solved a system of equations by substitution. In his work, he substituted an expression for one of the variables and solv
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He can conclude that the system of equations has no solution since one equation in it always results with false equivalency.

Hope this helps.

r3t40

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3 years ago
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3 years ago
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