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solniwko [45]
2 years ago
10

Maya spent her allowance on playing an arcade game a few times and riding the Ferris wheel more than once.

Mathematics
1 answer:
faust18 [17]2 years ago
6 0

Answer:

Sample Response: To write a two-variable equation, I would first need to know how much Maya’s allowance was. Then, I would need the cost of playing the arcade game and of riding the Ferris wheel. I could let the equation be cost of playing the arcade games plus cost of riding the Ferris wheel equals the total allowance. My variables would represent the number of times Maya played the arcade game and the number of times she rode the Ferris wheel. With this equation I could solve for how many times she rode the Ferris wheel given the number of times she played the arcade game.

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Let g (x) = 3x+2 and f (x) = x-2 / 3 find the value. g (f(2))
Romashka [77]

Answer: OPTION C.

Step-by-step explanation:

In order to solve the given exercise, you can follow these steps:

1. Given the following function f(x):

f(x)=\frac{x-2}{3}

You must substitute x=2 into the function f(x). Then:

f(2)=\frac{(2)-2}{3}

2. Evaluating, you get:

f(2)=\frac{0}{3}\\\\f(2)=0

3. Now, the next step is to substitute f(2)  into the function g(x):

g (x) = 3x+2\\\\g (f(2)) = 3(0)+2

4. Finally, evaluating, you get the following result:

g (f(2)) = 0+2\\\\g (f(2)) =2

You can identify that it matches with the Option C.

3 0
3 years ago
HELP ASAP PLEASE!!
Korolek [52]

Answer:

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3 0
2 years ago
Chuck and Blaire decided to share a 10
klemol [59]

Answer:

A. 7 1/6

Step-by-step explanation:

10 3/4 * 2/3=

43/4 * 2/3= 86/12

86/12 = 7 2/12 = 7 1/6

3 0
2 years ago
What is the ratio 9 1/2 to 12 2/3
vivado [14]
_ 9.5:12.6 That is the answer, btw the 6 is repeating
3 0
3 years ago
Find the extremum of f(x,y) subject to the given constraint, and state whether it is a maximum or a minimum. f(x,y)=4x2 2y2; 3x
nevsk [136]

For given f(x, y) the extremum: (12, 24) which is the minimum.

For given question,

We have been given a function f(x) = 4x² + 2y² under the constraint 3x+3y= 108

We use the constraint to build the constraint function,

g(x, y) = 3x + 3y

We then take all the partial derivatives which will be needed for the Lagrange multiplier equations:

f_x=8x

f_y=4y

g_x=3

g_y=3

Setting up the Lagrange multiplier equations:

f_x=\lambda g_x

⇒ 8x = 3λ                                        .....................(1)

f_y=\lambda g_y

⇒ 4y = 3λ                                         ......................(2)

constraint: 3x + 3y = 108                .......................(3)

Taking (1) / (2), (assuming λ ≠ 0)

⇒ 8x/4y = 1

⇒ 2x = y

Substitute this value of y in equation (3),

⇒ 3x + 3y = 108

⇒ 3x + 3(2x) = 108

⇒ 3x + 6x = 108

⇒ 9x = 108

⇒ x = 12

⇒ y = 2 × 12

⇒ y = 24

So, the saddle point (critical point) is (12, 24)

Now we find the value of f(12, 24)

⇒ f(12, 24) = 4(12)² + 2(24)²

⇒ f(12, 24) = 576 + 1152

⇒ f(12, 24) = 1728                             ................(1)

Consider point (18,18)

At this point the value of function f(x, y) is,

⇒ f(18, 18) = 4(18)² + 2(18)²

⇒ f(18, 18) = 1296 + 648

⇒ f(18, 18) = 1944                            ..............(2)

From (1) and (2),

1728 < 1944

This means, given extremum (12, 24) is minimum.

Therefore, for given f(x, y) the extremum: (12, 24) which is the minimum.

Learn more about the extremum here:

brainly.com/question/17227640

#SPJ4

6 0
1 year ago
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