Let
x-----> distance school to the park
y-----> distance park to the house
we know that
x=1/3 mile
y=1/2 mile
[distance from school to the house]=x+y----> (1/3+1/2)
The common denominator is (3*2)---> 6
=(2*1+3*1)/(3*2)----> 5/6 mile
the answer is
5/6 miles
8046.72~~~~~8047 that’s the answer
Answer:
First we need to calculate the distance between Clifton and Burlington by using Pythagorean theorem:
x² + 65² = 97²
=> x² = 97² - 65²
=> x² = 5184
=> x = √5184 = 72 (m)
The total distance from Aurora to Clifton through Burlington is: 65 + 72 = 137 (m)
We have: 137 - 97 = 40 (m)
So it is 40 m closer to travel from Aurora to Clifton directly than from Aurora to Clifton through Burlington
Cosine = adjacent / hypotenuse
cos (49)= x/27
27 * cos(49) = x
27 * 0.656 = x
x = 17.7
