Question

If 8 Superscript y Baseline = 16 Superscript y + 2, what is the value of y?

Answer 1

a - 8

Step-by-step explanation:

${8}^{y} = {16}^{y + 2} \\ \\ \therefore \: {2}^{3y} = {2}^{4(y + 2)} \\ \\ \therefore \: {2}^{3y} = {2}^{4y + 8} \\ \\ \therefore \: 3y = 4y + 8 \\ \\ \therefore \: 3y - 4y = 8 \\ \\ \therefore \: - y = 8 \\ \\ \therefore \: y = - 8$

Answer 2

Answer: I would say the answer would be C

Step-by-step explanation: Because the superscript of y is 8, and the baseline is 16, I think we have to divide that and we get 2 + 2= 4-

So y = -4

Hope this helps?