G^−m ÷ g^n
1st g^−m=1/g^m, hence g^−m ÷ g^n = (1/g^m) /(g^n)==> 1/(g^m)(g^(n)
==> 1/(g^m+n) or g^(-m-n)
Answer:
4
Step-by-step explanation:
(19-5)/3.5
14/3.5
4
Answer:
a1 = 34, d = 6.
Step-by-step explanation:
a1 = the first term = 34.
To find d subtract: 2nd term - first term , third term - second term and so on.
d = 40 - 34 = 6.
Also 46-40 = 6
WE get the same value 6 for the other given terms.
6 is added to each term to get the next term
If complex coefficients are allowed, the answer is 3.
If the polynomial must have real coefficients, then each complex root comes as a pair of complex conjugate roots.
Root -5 is real, so that is 1 root, and degree 1.
Root 1 + 4i is complex, so it must come with its complex conjugate, 1 - 4i. This adds 2 roots to the polynomial, and now we're up to degree 3.
Root -4i is also complex. It also must come with its complex conjugate, 4i. That adds two more roots, and the degree is 5.
Answer: The least possible degree is 5 with real coefficients.
Answer:
pick number 3 I think that's the one
