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crimeas [40]
4 years ago
13

Breann solved the system of equations below. What mistake did she make in her work? 2x + y = 5 x − 2y = 10 y = 5 − 2x x − 2(5 −

2x) = 10 x − 10 + 4x = 10 5x − 10 = 10 5x = 20 x = 4 2(4) + y = 5 y = −3 (5 points) Select one: a. She should have substituted 5 + 2x b. She combined like terms incorrectly, it should have been 4x instead of 5x c. She subtracted 10 from both sides instead of adding 10 to both sides d. She made no mistake
Mathematics
1 answer:
goldfiish [28.3K]4 years ago
5 0

Answer:

No mistake

Step-by-step explanation:

2x + y = 5

x - 2y = 10

y = 5 - 2x

x - 2(5 - 2x) = 10

x - 10 + 4x = 10

5x - 10 = 10

5x = 20

x = 4

2(4) + y = 5

y =  -3

She made no mistake

You can check by plugging in x = 4 and y = -3 into the original equations . They fit exactly.


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An electronic product contains 40 integrated circuits. The probability that any integrated circuit is defective is 0.01, and the
neonofarm [45]

Answer:

There is a 33.10% probability that there is at least one defective integrated circuit.

Step-by-step explanation:

For either integrated circuit, there are only two possible outcomes. Either they are defective, or they are not. This means that we can solve this problem using the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And \pi is the probability of X happening.

In this problem

The electonic product contains 40 integrated circuits, so n = 40.

The probability that any integrated circuit is defective is 0.01, so \pi = 0.01

What is the probability that there is at least one defective integrated circuit?

Either there is at least one defective integrated circuit, that is probability P(X > 0), or there are no defective integrated circuits, that is probability P(X = 0). The sum of these probabilities is decimal 1. We want to find P(X>0).

P(X > 0) + P(X = 0) = 1

P(X > 0) = 1 - P(X = 0)

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 0) = C_{40,0}.(0.01)^{0}.(0.99)^{40} = 0.6690

P(X > 0) = 1 - P(X = 0) = 1 - 0.6690 = 0.3310

There is a 33.10% probability that there is at least one defective integrated circuit.

3 0
3 years ago
Read 2 more answers
Serafina put a total of 42 cupcakes into packages. She put 6 cupcakes into each package. What is the total number of packages Se
Sedaia [141]

Answer:

7

Step-by-step explanation:

42 divided by 6 = 7 packages

8 0
2 years ago
PLZZZZ HELP ILY
Bingel [31]

Answer:

Seats increase by 4 each time a table is added.

Seats = 4 x #ofTables

Step-by-step explanation:

You have 6 seats with one table

You have 10 seats with two

14 with three

If you try out five, there will be 18 seats

6-10-14-18

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7 0
3 years ago
Need help will give brainliest easy math
natka813 [3]

Answer:

-1k?

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Follow all directions in the problem below.
kirill115 [55]

Answer: 110 test were purchased

Step-by-step explanation:

Set P = number of packets of 10 test

Total cost = $30 + $11 x P = $151

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P = $121/$11 = 11 packets were purchased

Test purchased = 11packets x 10 test/packet = 110 test were purchased

Answer: 110 test were purchased

<h3><em>Spymore</em></h3>
4 0
3 years ago
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