Answer:
X=9 and X=5
Step-by-step explanation:
So you want to get one side to equal zero so you can factor and find x. I recommend subtracting 14x and adding 45 to both sides so you don't have to deal with a negative quadratic.
X^2 - 14X +45 = 0
Now you can factor. Your looking for two factors that equal 45 and add to -14
All factors of 45:
1 and 45, 3 and 15, 5 and 9, -1 and -45,
-3 and -15, -5 and -9
So out of those combinations -5 and -9 both multiply to 45 and add up to -14 so these are our common factors
(X-5)(X-9)=0
X-5=0 add 5 to both sides X=5
X-9=0 add 9 to both sides X=9
Answer:
Step-by-step explanation:
The Pythagorean theorem is sqrt(a^2 + b^ 2) = c, so:
sqrt(22^2 + 8^2) = c
sqrt(548) = c
23.41 = c
<span>If you plug in 0, you get the indeterminate form 0/0. You can, therefore, apply L'Hopital's Rule to get the limit as h approaches 0 of e^(2+h),
which is just e^2.
</span><span><span><span>[e^(<span>2+h) </span></span>− <span>e^2]/</span></span>h </span>= [<span><span><span>e^2</span>(<span>e^h</span>−1)]/</span>h
</span><span>so in the limit, as h goes to 0, you'll notice that the numerator and denominator each go to zero (e^h goes to 1, and so e^h-1 goes to zero). This means the form is 'indeterminate' (here, 0/0), so we may use L'Hoptial's rule:
</span><span>
=<span>e^2</span></span>
Answer:
A
Step-by-step explanation:
gimme brainliest
Do you have a typo? ; < this maybe
