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sesenic [268]
3 years ago
6

What is the length of BD?

Mathematics
2 answers:
dlinn [17]3 years ago
5 0
The answer is 4.8.

One triangle has from length C - E 10 units.

The one to the right is 8 units from D - F.

So triangle BDF is 20% smaller in size than triangle ACE.  20% of 6 is 4.8, and that's your answer.
Tasya [4]3 years ago
3 0
The answer would be B
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Dmitrij [34]

Answer:

2.749

Step-by-step explanation:

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\sqrt{r_{1}^{2}+{r_{2}^{2}-2 r_{1} r_{2}cos(theta_{1} -theta_{2})

\sqrt{10^{2}+{3^{2}-2(1) (3)cos(225-(-91))

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3 years ago
Determine the current through each of the LEDs in the circuits below. Which LED will be
Anika [276]

a. I = 6. 1 × 10^-4 A

b. I = 2. 6 × 10^-3 A

c. I = 0. 04 A

The LED which would glow brightest is LED C with the greatest current and voltage

The LED which would be the most dim is LED B with low voltage and consequently low current.

<h3>How to determine the current</h3>

The formula for finding current

I = V/R

Where v = voltage

R = resistance

A. V = 12V

R = 4. 7 + 15 = 19. 7 kΩ = 19700 Ω in series

I = \frac{12}{19700}

I = 6. 1 × 10^-4 A

B. V = 9V

R = 4. 7 + 1 = 4. 7 kΩ = 4700Ω in series

I = \frac{12}{4700}

I = 2. 6 × 10^-3 A

C.  V=  12V

1/R = \frac{1}{750} + \frac{1}{1200} + \frac{1}{950 } = 3. 22 × 10^-3

R = \frac{1}{3. 22 * 10 ^-3} = 310. 56 Ω

I = \frac{12}{310. 56}

I = 0. 04 A

It is important to note that the brightness of a bulb depends on both current and voltage depending on whether the bulb it is in parallel or series.

The LED which would glow brightest is LED C with the greatest current and voltage

The LED which would be the most dim is LED B with low voltage and consequently low current.

Learn more about Ohms law here:

brainly.com/question/14296509

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8 0
2 years ago
I need help with a word problem .
BigorU [14]
What is the problem ?
4 0
3 years ago
Which complex number is a distance of sqrt17 from the origin on the complex plane?
lions [1.4K]

Let z=x+iy be a complex number. The distance from this complex number to the origin is

\sqrt{(x-0)^2+(y-0)^2}=\sqrt{x^2+y^2}.

Consider all options:

A. z=2+15i, then \sqrt{2^2+15^2}=\sqrt{229}.

B. z=17+i, then \sqrt{17^2+1^2}=\sqrt{290}.

C. z=20-3i, then \sqrt{20^2+(-3)^2}=\sqrt{409}.

D. z=4-i, then \sqrt{4^2+(-1)^2}=\sqrt{17}.

Answer: correct choice is D.

4 0
4 years ago
I need some help on this math
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Answer:

A

Step-by-step explanation:

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7 0
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