The correct axis of symmetry is x = -1.
Explanation:
Our equation is

.
This is in vertex form, which is
y = a(x-h)² + k, where (h, k) is the vertex.
In our equation, h corresponds with -1 and k corresponds with -3, making the vertex (-1, -3).
The axis of symmetry is the x-coordinate of the vertex; this makes the axis of symmetry for this equation x = -1.
Answer:
17
Step-by-step explanation:
8 + h^2
Let h = 3
8 + 3^2
We find the value of 3^2 first using PEMDAS
8 + 9
Then add
17
The result is 17
Hello,
x^2-y^2=(x+y)(x-y)
x^3-y^3=(x-y)(x²+xy+y²)
Let's use Horner's division
.........|a^3|a^2.|a^1..........|a^0
.........|1....|5....|6..............|8....
a=p...|......|p....|5p+p^2....|6p+5p^2+p^3
----------------------------------------------------------
.........|1....|5+p|6+5p+p^2|8+6p+5p^2+p^3
The remainder is 8+6p+5p^2+p^3 or 8+6q+5q^2+q^3
Thus:
8+6p+5p^2+p^3 = 8+6q+5q^2+q^3
==>p^3-q^3+5p^2-5q^2+6p-6p=0
==>(p-q)(p²+pq+q²)+5(p-q)(p+q)+6(p-q)=0
==>(p-q)[p²+pq+q²+5p+5q+6]=0 or p≠q
==>p²+pq+q²+5p+5q+6=0
And here, Mehek are there sufficients explanations?