Answer:
Number one is Linear, Number two is Exponential, and Number three is quadratic
Step-by-step explanation:
Answer:
I believe it is right by looking at this picture, but I am not certain
Answer:β=√10 or 3.16 (rounded to 2 decimal places)
Step-by-step explanation:
To find the value of β :
- we will differentiate the y(x) equation twice to get a second order differential equation.
- We compare our second order differential equation with the Second order differential equation specified in the problem to get the value of β
y(x)=c1cosβx+c2sinβx
we use the derivative of a sum rule to differentiate since we have an addition sign in our equation.
Also when differentiating Cosβx and Sinβx we should note that this involves function of a function. so we will differentiate βx in each case and multiply with the differential of c1cosx and c2sinx respectively.
lastly the differential of sinx= cosx and for cosx = -sinx.
Knowing all these we can proceed to solving the problem.
y=c1cosβx+c2sinβx
y'= β×c1×-sinβx+β×c2×cosβx
y'=-c1βsinβx+c2βcosβx
y''=β×-c1β×cosβx + (β×c2β×-sinβx)
y''= -c1β²cosβx -c2β²sinβx
factorize -β²
y''= -β²(c1cosβx +c2sinβx)
y(x)=c1cosβx+c2sinβx
therefore y'' = -β²y
y''+β²y=0
now we compare this with the second order D.E provided in the question
y''+10y=0
this means that β²y=10y
β²=10
B=√10 or 3.16(2 d.p)
Answer:
1:
<A=½(arcJL)=½(70+120)=35+60=95°
[inscribed angle is half of central angle]
2:
<W=½arcVX=½(130)=65°
[inscribed angle is half of central angle]
3.
<E=½(arcDC)=½(90)=45°
[inscribed angle is half of central angle]
4.
<R=½(arcXZ)=½(110+62)=86°
[inscribed angle is half of central angle]
5.
<B=½(arc DC)=½×104°=52°
[inscribed angle is half of central angle]
6.
<K=90°
[inscribed angle in a diameter is complementary]
<K+<J+<L=180°(sum of interior angle of a triangle]
<L=180°-90°-53°=37°
again
arc JK=2×<L=2×37=74°
I believe the answer is 65%. i'm not sure
