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Darya [45]
3 years ago
5

NEED HELP ASAP!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
aksik [14]3 years ago
3 0

Answer:

c

Step-by-step explanation:

39-15=24

24+15=39

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Answer:

  see below

Step-by-step explanation:

A multiplier on the function value moves its y-coordinate farther from the x-axis by that multiplier value. It is the stretch factor. Stretch factors less than 1 cause the graph to be compressed vertically.

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A multiplier on the independent variable means it doesn't need to be as large to give the same function value. That is, multiplication of x by a factor of k compresses the graph horizontally by that factor of k. Equivalently, it does a horizontal stretch by a factor of 1/k.

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Describe a triangle for which the centroid, circumcenter, incenter, and orthocenter are the same point. What features of this tr
hjlf

Answer:

An equilateral triangle

Step-by-step explanation:

Because an equilateral has a feature that all sides have the same length and all angles are of the same, it does not matter from which side and peak the centroid, circumcenter, incenter and orthocenter is created, they would always end up at the same point.

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Fill in the missing digits to find the base 2 representation of 59.
Anna007 [38]

Answer:

111011

Step-by-step explanation:

Following the binary rule we can find the base 2 presentation of the decimal number 59.

To find the binary equivalence of 59 we use the sum of powers of 2.

2^{0}=1

2^{1}=2

2^{2}=4

2^{3}=8

2^{4}=16

2^{5}=32

2^{6}=64

Now we take our number and find out what the binary number will by taking our largest number closest to the number first.

59 = 32

We chose the number 32 since 64 will be a larger value than 59.

We then check how much we have to add to 32 to get 59.

59 = 32 + 27

We then look for the closest number to 27 in our powers of 2.

59 = 32 + 16

Now we check again for how much we need left to get a total of 59.

59 = 32 + 16 + 11

Now we repeat the same process of finding which value in the powers of 2 are closest to the number.

59 = 32 + 16 + 8 + 3

59 = 32 + 16 + 8 + 2 + 1

Now since we already have a total of 59, our binary number will be all the numbers present will have a value of 1 and the numbers now used will have a number of 0.

32 16 8 4 2 1

This can also be represented as:

2^5 2^4 2^3 2^1 2^0

Now we have to include the numbers that we skipped to get the total binary number.

32 16 8 4 2 1  

1    1   1 0 1  1

This can be represented as:

59 = 32 16 + 8 + 0 + 2 + 1

1 1 1 0 1 1

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