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neonofarm [45]
3 years ago
15

Help!- How dilations are used in everyday life ? How about similarity transformations ?? How are they meaningful

Mathematics
1 answer:
Shalnov [3]3 years ago
3 0

Answer: Dilations can be used<em> in architecture in order to make a sample of their final design.</em> They must dilate the scale and measurements to match to their sample.

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<u>If you could please check out our you tube channel, </u>Evimero Academy

Thank you so much and have a wonderful day

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I have no idea how to do this
lakkis [162]
Add them all together and you’ll get your answer



sorry if this wasn’t any help or poorly explained
8 0
2 years ago
Help
mina [271]
"A dozen eggs and a dozen jellybeans" is the one comparison among the following choices given in the question that a teacher would most likely use for describing a mole. The correct option among all the options that are given in the question is the second option or option "B". I hope that the answer has helped you.
4 0
3 years ago
Read 2 more answers
Can anyone please help me?
DerKrebs [107]

Answer:

B. x =1 , y = -5

Step-by-step explanation:

So, what we can do is to simply plug in all of the equations and see which one fits. Equation: x - y = 6

A. x =1 , y = -6

1 -(-6) = 6

1 + 6 = 7

A would be incorrect.

B. x = 1, y = -5

1 - (-5) = 6

1 + 5 = 6

Therefore, B would be correct.

5 0
3 years ago
Read 2 more answers
Find the equation of the line.
vovikov84 [41]

Answer:

<em>y = - x - 10 </em>

Step-by-step explanation:

y - (- 3) = - (x + 7)

<em>y = - x - 10</em>

3 0
3 years ago
An equilateral ∆ has sides of length 16 cm. Find the length of an altitude.
inn [45]

The length of the altitude is 8\sqrt{3}

Explanation:

Let ABC be an equilateral triangle.

It has sides of length 16 cm

Let AD be the altitude of the triangle.

We need to determine the length of an altitude.

Let AC = 16 cm and CD = 8 cm

Let us consider the right angled triangle ADC

Using the Pythagorean theorem, we have,

AC^2=AD^2+DC^2

Substituting the values, we get,

 16^2=AD^2+8^2

 256=AD^2+64

 192=AD^2

8\sqrt{3}=AD

The length of the altitude is 8\sqrt{3}

5 0
3 years ago
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