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neonofarm [45]
2 years ago
15

Help!- How dilations are used in everyday life ? How about similarity transformations ?? How are they meaningful

Mathematics
1 answer:
Shalnov [3]2 years ago
3 0

Answer: Dilations can be used<em> in architecture in order to make a sample of their final design.</em> They must dilate the scale and measurements to match to their sample.

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5.1x=-15.3 solve for x
LekaFEV [45]

Answer


x=-3


Hope it helps!!

3 0
3 years ago
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Helpppp I attached a ss
joja [24]

Answer:

the answer is 7×9=(7×10)-(7×1)

5 0
3 years ago
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The table shows the distance Shannon ran over a week.
Sedbober [7]

Answer:

Shannon run 1.5 km more on Friday than on Saturday.

Step-by-step explanation:

From the given table

  • Distance run on Friday = 4/2 = 2 km
  • Distance run on Saturday = 1/2 = 0.5 km

  • In order to run how many more kilometers Shannon run on Friday than on Saturday, we need to subtract the distance run on Saturday from the distance run on Friday.

i.e.

Friday run - Saturday run =  2 - 0.5

                                          = 1.5 km

Thus, Shannon run 1.5 km more on Friday than on Saturday.

8 0
2 years ago
A study of peach trees found that the average number of peaches per tree was 725. The standard deviation of the population is 70
TEA [102]

Answer:

She needs to sample 189 trees.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.95}{2} = 0.025

Now, we have to find z in the Ztable as such z has a pvalue of 1 - \alpha.

That is z with a pvalue of 1 - 0.025 = 0.975, so Z = 1.96.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

The standard deviation of the population is 70 peaches per tree.

This means that \sigma = 70

How many trees does she need to sample to obtain an average accurate to within 10 peaches per tree?

She needs to sample n trees.

n is found when M = 10. So

M = z\frac{\sigma}{\sqrt{n}}

10 = 1.96\frac{70}{\sqrt{n}}

10\sqrt{n} = 1.96*70

Dividing both sides by 10:

\sqrt{n} = 1.96*7

(\sqrt{n})^2 = (1.96*7)^2

n = 188.2

Rounding up:

She needs to sample 189 trees.

3 0
3 years ago
A map of a rectangular park has a length of 4 inches and a width olo and a width of 6 inches. It uses a scale of 1 inch for ever
Zielflug [23.3K]

Answer:

The actual area of the park is 21,600 miles square.

Step-by-step explanation:

<u>Step 1: Calculate the area of the park</u>

<em>Area of rectangle = Length x width</em>

Length = 4 inches

Width = 6 inches

Scale factor is given as, 1 inch = 30 miles.

So, converting the length and width in miles by using the scale factor, we get

Length = 4 * 30 = 120 miles

Width =  6 * 30 = 180 miles

The formula of finding the area of an rectangle is:

<em>Area = length x width</em>

By putting the values in equation, we get

Area = 120 x 180

Area = 21,600 miles square

Therefore, the actual area of the park is 21,600 miles square.

8 0
3 years ago
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