Perpendicular lines will have negative reciprocal slopes. Example : if u r given a slope of 1/3, to find the negative reciprocal, flip the slope and change the sign. So the negative reciprocal of 1/3 is -3/1 or just -3. So slope 1/3 and slope -3 are perpendicular.
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equation 2 :
4x + 2y = 6
2y = -4x + 6
y = -2x + 3...the slope here is -2....a perpendicular line will have a slope of 1/2.
y = (a/3)x - 6......so we have to make a/3 = 1/2......1.5/3 = 1/2
so a = 1.5
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eq. 2 : 3/4x + 2
not sure what the entire equation is.....but it looks to have a slope of 3/4. That means a perpendicular line will have a slope of -4/3.
3y + ax = 9
3y = -ax + 9
y = (-a/3)x + 3.....therefore, a has to be 4
Answer:
it's ax+b form answer is Q(x-2)=4x-6
Step-by-step explanation:
ax+b=Q(x),Q(x-2)=a(x-2)+2
Q(3x)=a(3x)+b=12x+2, 3a=12 =>a=4,b=2
the original q of x is 4x+2
Q of x-2 =4(x-2)+2=4x-8+2=4x-6
(4/3^2 aka 4 over 3 (fraction) to the power of 2 equals...? Please help me lol
The minimum area is obtained if the box is a cube.
⇒ The lengths of the edges are:
Answer:
|x-2| = 6
The equation will be satisfied only for -4 and 8
The answer is B.
Hope this helps!