Challenge accepted.
CE / 2 = 3JQ / 7
7(CE) = 2(3JQ)
7CE = 6JQ
/6Q /6Q
7CE
/6Q = J
Answer is A. I ain't fully sure cuz I'm only in grade 9 lol
the one where they are diagonal from one another
1) If <em>x</em> is the number of years Naicul works, then the corporate job would earn him
49600<em>x</em> + 2000
dollars, while the teaching job would earn
50000<em>x</em>
dollars. Solve for <em>x</em> such that these two earnings are equal:
49600<em>x</em> + 2000 = 50000<em>x</em>
400<em>x</em> = 2000
<em>x</em> = 5
2) a) At a speed of 6.7 m/s, DJ would finish the race in
(100 m) / (6.7 m/s) ≈ 14.93 s
2) b) If DJ is given a headstart of <em>y</em> seconds, then Usain finishes the race in (9.58 + <em>y</em>) seconds. Solve for <em>y</em> such that this time matches DJ's time from part (a) :
14.93 s = (9.58 + <em>y</em>) s
<em>y</em> ≈ 5.35 s
Answer:
A
Step-by-step explanation:
Let's check
The formula is 3 *6^(n-1)
The first generation had 3 rabbits
3*6(1-1) = 3*6^0 = 3*1 =3
That works
Try it again with the 2nd generation
n is the number of generation
3*6^(2-1)= 3*6^1 = 18
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We can deduce the formula
The initial number of rabbits is 3
Each time we multiply by 6
So for the generation number n the formula will be :
3*6^(last generation-first generation)
3*6^(n-1)
