Can someone answer This, please?

The roof of the building shown below has a span of 48 feet. The rafters upon which the roof is laid are 30 feet long, including

anyanavicka [17]

Solution :

Given :

Span of the roof = 48 feet

Length of the rafter = 30 feet (including the 4 feet overhung)

So, for the 30 feet long rafter, 26 feet will be rafter length from the high point of the roof to the edge of the roof and 4 feet will be the roof overhung.

Therefore, the horizontal span per rafter is

$=\frac{48}{2}$

= 24 feet

a). So the rise of the roof is $= \sqrt{(26)^2-(24)^2}$

= 10 feet

b). Pinch of the roof is $=\frac{\text{rise}}{\text{run}}$

$=\frac{10}{24}$

$=\frac{5}{12}$

c). The percent of the roof used as overhung is

$=\frac{4+4}{60}\times 100$

$=\frac{80}{6}$

= 13.33 %

8 0

3 years ago

Suppose that 75% of all trucks undergoing a brake inspection at a certain inspection facility pass the inspection. Consider grou

RSB [31]

Answer:

b) 0.2961

c) 0.2251

d) Mean = 11.25, Standard deviation = 1.667

Step-by-step explanation:

We are given the following information:

We treat trucks undergoing a brake inspection passin as a success.

P( trucks undergoing a brake inspection passes the test) = 75% = 0.75

a) Conditions for binomial probability distribution

There are n independent trial.
Each trial have a success probability p
The probability of success is same for all trials.

Then the number of trucks undergoing a brake inspection follows a binomial distribution, where

$P(X=x) = \binom{n}{x}.p^x.(1-p)^{n-x}$

where n is the total number of observations, x is the number of success, p is the probability of success.

Now, we are given n = 15

b) P(proportion of groups will between 8 and 10 trucks pass the inspection)

We have to evaluate:

$P(8\leq x \leq 10) = P(x = 8) + P(x = 9) + P(x = 10)\\= \binom{15}{8}(0.75)^8(1-0.75)^7 + \binom{15}{9}(0.75)^9(1-0.75)^6 + \binom{15}{10}(0.75)^{10}(1-0.75)^5\\= 0.0393 + 0.0917 + 0.1651\\= 0.2961$

c) P( exactly 3 trucks fail the inspection)

p = 0.25

$P(x = 3)\\= \binom{15}{3}(0.25)^3(1-0.25)^{12}\\=0.2251$

d) Mean and standard deviation

$\mu = np = 15(0.75) = 11.25\\\sigma = \sqrt{np(1-p)} = \sqrt{15(0.75)(1-0.75)} = 1.667$

6 0

3 years ago

Which of the following statements is true?. . A.A tangent is never a secant.. B.A secant is always a chord.. C.A chord is always

skelet666 [1.2K]

The correct answer is:

A) A tangent is never a secant.

Explanation:

A tangent is a line that touches a circle in exactly one point. A secant is a line that touches a circle in two different points.

Since a tangent only touches once and a secant touches twice, there is no way a tangent can be a secant.

3 0

3 years ago

Uche pumps gasoline at a rate of 18\,\dfrac{\text{L}}{\text{min}}18 min L 18, start fraction, start text, L, end text, divided

Fiesta28 [93]

Answer:

Uche's pumping rate is 300 mL/s.

Step-by-step explanation:

Given:

Uche pumps gasoline at a rate of 18 L/min.

Now, to find Uche's pumping rate in mL/s.

The rate at which Uche pumps gasoline = 18 L/min.

So, to get the pumping rate in mL/s we use convert L/min to mL/s by using conversion factor:

1 L/min = 16.6667 mL/s.

18 L/min = 16.6667 × 18 mL/s.

18L/min = 300 mL/s.

Therefore, Uche's pumping rate is 300 mL/s.

8 0

3 years ago

Jesse practices the trumpet for a total of 165 minutes during the first week of school. He practices for 245 minutes during the

JulsSmile [24]

So u can make shur your Awser is resinuble

8 0

4 years ago