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3 years ago

Write nine hundred and eight tenths as a decimal number.

Mathematics

1 answer:

mariarad [96]3 years ago

6 0

Answer:

900.8

Step-by-step explanation:

Required to find

Decimal representation of 9 hundred and 8 tenths

9 hundred $=9\times 100$

8 tenths $=8\times\frac{1}{10} =0.8$

Therefore decimal representation= 900+0.8= 900.8

(optional)

Fractional representation

$=900.8=\frac{9008}{10} =\frac{4504}{5}$

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Elevando um certo numero natural,maior do que zero,ao expoente 101 encontrarmos como resposta 1. Qual é esss numero? 101 A) 0 B)

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Answer:

B) 1

Step-by-step explanation:

The computation of the number is shown below:

Since the number 1 would be raised to any exponent so it always remains be 1

= 1 × 1 × 1 × 1 × 1 × 1 × 1 × 1 × 1

= 1

Therefore the option B is correct

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3 years ago

How do you simplify 8*1/10

Lelechka [254]

Answer:

Improper its 81/10

Step-by-step explanation:

8 1/10~ we should multiply denominator with whole number then add numerator:

10 x 8 = 80+ 1 = 81

In improper its- 81/10

Hope this helps :D

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3 years ago

What value should be added to the expression to create a perfect square?

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3 years ago

Assume that a procedure yields a binomial distribution with a trial repeated n = 5 times. Use some form of technology to find th

Digiron [165]

Answer:

$P(X = 0) = 0.0263$

$P(X = 1) = 0.1407$

$P(X = 2) = 0.3012$

$P(X = 3) = 0.3224$

$P(X = 4) = 0.1725$

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Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem we have that:

$n = 5, p = 0.517$

Distribution

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{5,0}.(0.517)^{0}.(0.483)^{5} = 0.0263$

$P(X = 1) = C_{5,1}.(0.517)^{1}.(0.483)^{4} = 0.1407$

$P(X = 2) = C_{5,2}.(0.517)^{2}.(0.483)^{3} = 0.3012$

$P(X = 3) = C_{5,3}.(0.517)^{3}.(0.483)^{2} = 0.3224$

$P(X = 4) = C_{5,4}.(0.517)^{4}.(0.483)^{1} = 0.1725$

$P(X = 5) = C_{5,5}.(0.517)^{5}.(0.483)^{0} = 0.0369$

6 0

3 years ago

Only 3 choices please help!

scoray [572]

The second choice becouse of the total being changed

5 0

3 years ago