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4 years ago

Volume with cubes with fraction lengths

Mathematics

1 answer:

Greeley [361]4 years ago

4 0

Answer:

You could fit 48 cubes with side lengths of 1/3 cm inside a rectangular prism with dimensions of 1 cm X 2 2/3 cm X 2/3 cm.

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Which angles are linear pairs. check all that apply

snow_tiger [21]

bro where is the pic???? how are we supposed to answer this?

6 0

3 years ago

Read 2 more answers

An article contained the following observations on degree of polymerization for paper specimens for which viscosity times concen

devlian [24]

Answer:

(a) A 95% confidence interval for the population mean is [433.36 , 448.64].

(b) A 95% upper confidence bound for the population mean is 448.64.

Step-by-step explanation:

We are given that article contained the following observations on degrees of polymerization for paper specimens for which viscosity times concentration fell in a certain middle range:

420, 425, 427, 427, 432, 433, 434, 437, 439, 446, 447, 448, 453, 454, 465, 469.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean = $\frac{\sum X}{n}$ = 441

s = sample standard deviation = $\sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }$ = 14.34

n = sample size = 16

$\mu$ = population mean

Here for constructing a 95% confidence interval we have used One-sample t-test statistics as we don't know about population standard deviation.

So, 95% confidence interval for the population mean, $\mu$ is ;

P(-2.131 < $t_1_5$ < 2.131) = 0.95 {As the critical value of t at 15 degrees of

freedom are -2.131 & 2.131 with P = 2.5%}

P(-2.131 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 2.131) = 0.95

P( $-2.131 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $2.131 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

P( $\bar X-2.131 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+2.131 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

95% confidence interval for $\mu$ = [ $\bar X -2.131 \times {\frac{s}{\sqrt{n} } }$ , $\bar X +2.131 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $441-2.131 \times {\frac{14.34}{\sqrt{16} } }$ , $441+2.131 \times {\frac{14.34}{\sqrt{16} } }$ ]

= [433.36 , 448.64]

(a) Therefore, a 95% confidence interval for the population mean is [433.36 , 448.64].

The interpretation of the above interval is that we are 95% confident that the population mean will lie between 433.36 and 448.64.

(b) A 95% upper confidence bound for the population mean is 448.64 which means that we are 95% confident that the population mean will not be more than 448.64.

6 0

3 years ago

F(x)=tan(x)

AleksAgata [21]

Tan(x) = sin(x) / cos(x). Therefore, tan(x) pi/2 = 1/0, which doesn't exist. Imagine that, instead of 0, it's a number incredibly close to 0. The smaller the number in the denominator, the bigger the outcome. Therefore, we can think of 1/0 as infinity, or approaching infinity as one gets closer to 1/0. This is the same result approaching from the negative side, only it's negative infinity. If x=0, it's 0/1 instead (sin 0=0, cos 0=1). Anything divided by 1 is itself, so as x approaches 0, so does f(x).

7 0

3 years ago

Please help me with this

zhannawk [14.2K]

I’m pretty sure it’s 82

6 0

3 years ago

Find an equation of the line that satisfies the given condition. (Let x be the independent variable and y be the dependent varia

NeTakaya

Answer:

y = 4

Step-by-step explanation:

A line parallel to the x-axis has the same value of the dependent variable (y) for all the values of the independent variable (x). Hence, the line would be an horizontal line that passes through the y-axis and never meets the x-axis. Since this line satisfies the condition of passing through the coordenates (x,y), (-6,4), then the equation is equal to the value of the coordinate y.

Therefore, the equation of a line that satisfies these two conditions is y = 4.

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8 0

3 years ago