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Damm [24]
2 years ago
13

Find a solution to 3cos(θ)=−0.862 in radians

Mathematics
1 answer:
eimsori [14]2 years ago
7 0
3cos(\theta) = -0.862
\frac{3cos(\theta)}{3} = \frac{-0.862}{3}
cos(\theta) = -\frac{431}{1500}
cos^{-1}[cos(\theta)] = cos^{-1}(-\frac{431}{1500})
\theta = 106.6983737\°
\theta = 1.86223792^{r}
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Find the value of 3 square root of 1000​
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The answer to this is 10
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Help!!!!!!!!!!!<br> Solve for x<br> x+11+8x=29<br> Explain how you got the answer please!
dolphi86 [110]
X + 11 + 8x = 29. We need to solve for x.
First, on the left side, you have "x" and "8x": You can always add 2 numbers with the same variable, so you have 1 number: x + 8x = 1x + 8x = (1+8)x = 9x

So we get:
9x + 11 = 29

Now subtract 11 from both sides (You can't do any operation if you don't do it both sides), so you can get the variable alone on the left side, and the numbers on the right side:
9x + 11 = 29
9x + 11 - 11 = 29 - 11
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Now divide both sides by 9, so you can transform the coefficient of x to one, and have the numeric value of x on the right side:
9x = 18
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So x+11+8x = 29 for x = 2.

You can recheck your answer (very important):
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The answer has been approved.

Hope this Helps! :)
8 0
3 years ago
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Diego's history teacher writes a test for the class with 26 questions. The test is worth 123 points and has two types of questio
maxonik [38]

Answer:

The number of essay questions on the test were 9

Step-by-step explanation:

Given as :

Total number of questions in a test = 26

Total points for the 26 questions = 123

The point for each multiple choice questions = 3

The point for each essay questions = 8

Let The number of multiple choice questions = m

Let The number of essay questions = e

<u>Now, According to question</u>

Total number of questions in a test = number of multiple choice questions +  number of essay questions

Or, m + e = 26         .....A

Again

Total points for the 26 questions =  point for each multiple choice questions  ×  number of multiple choice questions + point for each essay questions × number of essay questions

i.e 3 × m + 8 × e = 123

Or, 3 m + 8 e = 123          .......B

Solving the equation we get

8 × ( m + e ) - (3 m + 8 e) = 8 × 26 - 123

Or, 8 m + 8 e - 3 m - 8 e = 208 - 123

Or,(8 m -  3m) + (8 e - 8 e) = 85

Or, 5 m + 0 = 85

∴  m = \dfrac{85}{5}

i.e m = 17

So,The number of multiple choice questions = m = 17

Put the value of m into eq A

∵ m + e = 26

Or, e = 26 - 17

i.e e = 9

So, The number of essay questions = e = 9

Hence, The number of essay questions on the test were 9 . Answer

7 0
3 years ago
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