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Damm [24]
3 years ago
13

Find a solution to 3cos(θ)=−0.862 in radians

Mathematics
1 answer:
eimsori [14]3 years ago
7 0
3cos(\theta) = -0.862
\frac{3cos(\theta)}{3} = \frac{-0.862}{3}
cos(\theta) = -\frac{431}{1500}
cos^{-1}[cos(\theta)] = cos^{-1}(-\frac{431}{1500})
\theta = 106.6983737\°
\theta = 1.86223792^{r}
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What is pq^5 pq^2 Greatest Common Factor????????
algol [13]
Pq^5 and pq^2

the GCF would be : pq^2
7 0
3 years ago
Location Score Factor (100 points each) Weight A B C Convenience 0.15 89 78 84 Parking facilities 0.20 75 93 98 Display area 0.1
Olin [163]

The maximum composite score from A, B, and C is B.

The computation of the composite score for each location is shown below

The composite score for A is,

= 0.15 × 89 + .20 × 75 + 0.18 × 92 + 0.27 × 92 + 0.10 × 93 + 0.10 × 90

= 88.05

<h3>What is the composite score?</h3>

The Composite score is the average of your four test scores, rounded to the nearest whole number. Fractions less than one-half are rounded down; fractions one-half or more are rounded up.

The composite score for B is

= 0.15 × 78 + .20 × 93 + 0.18 × 90 + 0.27 × 93 + 0.10 × 97 + 0.10 × 96

= 90.91

The composite score for C is

= 0.15 × 84 + .20 × 98 + 0.18 × 87 + 0.27 × 82 + 0.10 × 84 + 0.10 × 95

= 87.90

Therefore for computing the composite score for each location we simply multiply the weight by the A location and in the same manner as A, B, and C

b. The maximum composite score from A, B, and C is B.

To learn more about the composite score visit:

brainly.com/question/23458524

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5 0
2 years ago
. Out of 40 pupils only 30 pupils submitted their project on time
Verizon [17]

Answer:

75 %

Step-by-step explanation:

To solve for the above question,

The percentage of pupils that submitted their project on time

= Number of pupils that submitted their project on time/Number of pupils × 100

Number of pupils that submitted their project on time = 30 pupils

Number of pupils = 40 pupils

= 30/40 × 100

= 75 %

The percent of the pupils that submitted their project on time is 75%

3 0
3 years ago
Find the sum of 4x^3+2x^2-4x+3 and 7x^3-4x^2+7x+8
Alchen [17]

The sum means addition.

Add  the like terms together.

4x^3+2x^2-4x+3

+ 7x^3-4x^2+7x+8

4x^3 + 7x^3 = 11x^3

2x^2 + -4x^2 = -2x^2

-4x +7x = 3x

3 +8 = 11

The answer is : 11x^3 - 2x^2 + 3x + 11

4 0
3 years ago
Read 2 more answers
Why do I need to pay to see answers....
Korvikt [17]
Same girl oh my god it won’t let me ask anymore questions. Not my fault my math teacher gave me 30 questions to ask
8 0
3 years ago
Read 2 more answers
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