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Andre45 [30]
2 years ago
9

All basketballs at a sporting goods store were marked down 25% during the first week of a sale. During the third week, all remai

ning basketballs were marked down an additional 30%. If a basketball was originally $22, how much does it cost during the third week?
Mathematics
1 answer:
QveST [7]2 years ago
4 0

Answer:

selling price= $9.9

Step-by-step explanation:

Giving the following information:

During the third week, all remaining basketballs were marked down an additional 30%.

Original price= $22

<u>To calculate the selling price in the third week, we need to use the following formula:</u>

<u></u>

selling price= original price*(1 - markdown)

selling price= 22*(0.45)

selling price= $9.9

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BRAINLIEST TO CORRECT QUICKLY
Pani-rosa [81]

Answer:

-6 3/8 < -7/8

Step-by-step explanation:

Answer:

-6 3/8 < -7/8

Showing Work

Using the given inputs:

-6 3/8 -7/8

Rewriting these inputs as improper fractions:

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Since we have like denominators we compare the inputs by the numerators:

Therefore, comparison shows:

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8 0
2 years ago
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Merrill is playing a simple game of dice. For every 6 rolled, Merrill will win $5. For any other number, he must pay $2. How muc
Schach [20]

Solution -

The probability of getting 6 from a single roll of a fair dice = \frac{1}{6}

The probability of getting any other number rather than 6 would be 1-\frac{1}{6} = \frac{5}{6}

So when the outcome is 6, then he wins $5 ,otherwise he has to pay $2

So

E(X) = Expectation value = (\frac{1}{6} )(5) - (\frac{5}{6} )(2)                                    ( ∵ $5 gain so +ve and $2 loss so -ve)

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∴ So Merrill will lose \frac{5}{6} dollar


7 0
3 years ago
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A container holds 16 pints of lemonade. How much is this in gallons
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3 years ago
The diameter of a table is 5 feet. What is the circumference
gulaghasi [49]

if the diameter is 5, then its radius is half that, or 2.5.


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Use Distance Formula

Step-by-step explanation:

You can find the distance between two points by using the distance formula which by definition is \sqrt{(x_2-x_1 )^2+(y_2-y_1)^2 }

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Point 1 is (-1, 8)

Point 2 is (-3, -2)

You equation would look like:

\sqrt{(-3-(-1))^2+(-2-8)^2}

This simplifies to \sqrt{(-2)^2+(-10)^2}

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