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Eva8 [605]
3 years ago
5

What is the coefficient of

Mathematics
1 answer:
Serjik [45]3 years ago
6 0

Answer:

14

Step-by-step explanation:

The coefficient is the number before the degree. In this equation, it looks to be that the number before the 6th degree is 14.

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What's -18÷(1-4+-2-4) explain pls need help​
Mrac [35]

Answer:

the answer is 2.

Step-by-step explanation:

i dont know how to explain sorry

4 0
3 years ago
Which expression is equivalent to 36q- 4r +12? A) 6(6q-4r+2) B) 9(4q-4r+12) C) 4(9q-r+3)
lakkis [162]
C) 4(9q-r+3)
because you distribute the 4 to the inside of the parentheses. So, 4 x 9q = 36q, 4 x -r = -4r, 4 x 3 = 12. 36q-4r+12 is your answer when you distribute.
8 0
3 years ago
Mahni plans to spend the next 12 weeks saving some of her income. She will save $x a week for the first 6 weeks and then $(2x −
Ulleksa [173]

$x=213$

For first six weeks she saved 213$

Now

For next 6weeks

\\ \sf\longmapsto 2x-30=2(213)-30=426-30=396\$

Total savings:-

.\\ \sf\longmapsto 396+213=609\$

4 0
3 years ago
Read 2 more answers
Determine whether the set W is a subspace of R3 with the standard operations. If not, state why.
poizon [28]

Answer:

Step-by-step explanation:

From the given information.

R3 is a vector space over the field R, where R is the set of real numbers.

Where;

The set W = {(0, x2, x3): x2 and x3 are real numbers} is the subspace of \Re³

To proof:

(0,0,0) ∈ W ⇒ W ≠ ∅

Suppose u and v is an element of W;

i.e.

u,v ∈ W (which implies that) ⇒ u (0,x2,x3) and v = (0,y2,y3) are  real numbers.

Then

u+v = (0,x2,x3) +(0, y2, y3)

u+v = (0,x2+y2, x2+y3) ∈ W

⇒ u+v ∈ W  ----- (1)

Now, if we take any integer to be an element  of the real number \Re

i.e

∝ ∈ \Re

∝*\Re = ∝(0,x2,x3)

∝*\Re = (0,x2,x3) ∈ W

⇒ ∝*u ∈ W ------(2)

Thus from (1) and (2), W is a subspace of \Re³

7 0
3 years ago
Of all the numbers whose difference is 36​, find the two that have the minimum product
scZoUnD [109]

Answer:

54,18

Step-by-step explanation:

Let one of the numbers be x. The other number be represented as 36-x

(x-(36-x ) = 36

open brackets

x - 36 + x  =  36

x + x = 36+ 36 = 72

2x = 72

x = 72/2 = 36

x =  36

The product can then be represented as y = x(36-x) or y=36x-x²

 The maximum or minimum is always on the axis of symmetry which has the formula x=-b/2a.

In our case, the axis of symmetry is -36/-2, so x=18.

 

If one number is 18 and the 2 numbers differentiate by 36, the other number is 18 + 36 = 54

So the 2 numbers are 18 and 54 and the minimum product is 972

8 0
3 years ago
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