I think this is the answer
(-2,5)
(0,4)
(2,3)
(4,2)
Answer:
0.1225
Step-by-step explanation:
Given
Number of Machines = 20
Defective Machines = 7
Required
Probability that two selected (with replacement) are defective.
The first step is to define an event that a machine will be defective.
Let M represent the selected machine sis defective.
P(M) = 7/20
Provided that the two selected machines are replaced;
The probability is calculated as thus
P(Both) = P(First Defect) * P(Second Defect)
From tge question, we understand that each selection is replaced before another selection is made.
This means that the probability of first selection and the probability of second selection are independent.
And as such;
P(First Defect) = P (Second Defect) = P(M) = 7/20
So;
P(Both) = P(First Defect) * P(Second Defect)
PBoth) = 7/20 * 7/20
P(Both) = 49/400
P(Both) = 0.1225
Hence, the probability that both choices will be defective machines is 0.1225
You can find the degree classification by what is the greatest power shown in the polynomial. In this case, your answer is 2. Remember, it will be easier to find the degree when you order the terms from greatest to least by powers.
Answer:
There are 51 boxes all together.
Step-by-step explanation:
Since there are three separate, equal-size boxes, and inside each box there are four separate small boxes, and inside each of the small boxes there are three even smaller boxes, to determine how many boxes are there all together, the following calculation must be done:
3 + 3 x 4 + 3 x 4 x 3 = X
3 + 12 + 36 = X
51 = X
Therefore, there are 51 boxes all together.
