Answer:
- Positive at (-9, 2)
- Negative at ( -oo, -9) or (2, + oo)
Step-by-step explanation:
<u>Given function</u>
<u>Getting zero's</u>
- -2x^2 - 14x + 36 = 0
- x^2 + 7x - 18 = 0
- x = ( -7 ± √(49 +72))/2 = ( -7 ± 11)/2
- x = - 9 and x = 2
<u>As the x^2 has negative coefficient, the function is positive between -9 and 2</u>
<u>And it is negative at:</u>
- x < -9 and
- x > 2
- or
- ( -oo, -9) or (2, + oo)
This will be an educated guess but I think the answer would be $565000
Okay is B
HOPE IT HELPS YALL
Answer:
<h3>#1</h3>
The normal overlaps with the diameter, so it passes through the center.
<u>Let's find the center of the circle:</u>
- x² + y² + 2gx + 2fy + c = 0
- (x + g)² + (y + f)² = c + g² + f²
<u>The center is:</u>
<u>Since the line passes through (-g, -f) the equation of the line becomes:</u>
- p(-g) + p(-f) + r = 0
- r = p(g + f)
This is the required condition
<h3>#2</h3>
Rewrite equations and find centers and radius of both circles.
<u>Circle 1</u>
- x² + y² + 2ax + c² = 0
- (x + a)² + y² = a² - c²
- The center is (-a, 0) and radius is √(a² - c²)
<u>Circle 2</u>
- x² + y² + 2by + c² = 0
- x² + (y + b)² = b² - c²
- The center is (0, -b) and radius is √(b² - c²)
<u>The distance between two centers is same as sum of the radius of them:</u>
<u>Sum of radiuses:</u>
<u>Since they are same we have:</u>
- √(a² + b²) = √(a² - c²) + √(b² - c²)
<u>Square both sides:</u>
- a² + b² = a² - c² + b² - c² + 2√(a² - c²)(b² - c²)
- 2c² = 2√(a² - c²)(b² - c²)
<u>Square both sides:</u>
- c⁴ = (a² - c²)(b² - c²)
- c⁴ = a²b² - a²c² - b²c² + c⁴
- a²c² + b²c² = a²b²
<u>Divide both sides by a²b²c²:</u>
Proved
Hey there! :)
PARENTHESES
EXPONENTS
MULTIPLICATION
DIVISION
ADDITION
SUBTRACTION
First is dividing
56 ÷ 34 = 56/34
56/34 = 28/17
56 ÷ 2 = 28
34 ÷ 2 = 17
Then multiply by y
28/17 × y = 28/17·y = 28y/17 or 28/17y
At last, you add 12
28y/17 + 12 = 28y/17 + 12
Your answer is: 28y/17 + 12
Hope this helps :)
