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3 years ago

10

For Tran thank you appreciate it

1 answer:

Anestetic [448]3 years ago

3 0

Step-by-step explanation:

Let alpha be the unknown angle. We can set up our sine law as follows:

$\frac{ \sin( \alpha ) }{5 \: m} = \frac{ \sin(42) }{3.6 \: m }$

or

$\sin( \alpha ) = \frac{5 \: m}{3.6 \: m} \times \sin(42) = 0.929$

Solving for alpha,

$\alpha = arcsin(0.929) = 68 \: degrees$

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The ages of armadillos are normally distributed, with a mean of 14 years and a standard deviation of 1.2. Approximately what per

mars1129 [50]

Answer:

20.33%

Step-by-step explanation:

4 0

3 years ago

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Tems11 [23]

QUESTION A

The given multiplication problem is

$\frac{39}{64} \times \frac{8}{13}$

Factor each term to obtain;

$\frac{13\times 3}{8\times8} \times \frac{8}{13}$

Cancel out the common factors to obtain;

$\frac{1\times 3}{8\times1} \times \frac{1}{1}$

Simplify to get;

$\frac{3}{8}$

QUESTION B

The given multiplication problem is

$\frac{2}{3}\times \frac{1}{5}\times \frac{4}{7}$

This the same as

$\frac{2\times 1\times 4}{3\times 5\times 7}$

This simplifies to;

$\frac{8}{105}$

QUESTION C

The given problem is

$\frac{3}{5}\times \frac{10}{12} \times \frac{1}{2}$

This is the same as

$\frac{3}{5}\times \frac{5}{6} \times \frac{1}{2}$

$=\frac{1}{1}\times \frac{1}{2} \times \frac{1}{2}$

This simplifies to

$=\frac{1}{4}$

QUESTION D.

The given expression is

$\frac{4}{9}\times 54$

Factor the 54 to obtain;

$\frac{4}{9}\times 9\times 6$

Cancel the common factors to get;

$\frac{4}{1}\times 1\times 6$

This simplifies to;

$=24$

QUESTION E

The given problem is

$20\times 3\frac{1}{5}$

Convert the mixed numbers to improper fraction to obtain;

$=20\times \frac{16}{5}$

$=4\times5 \times \frac{16}{5}$

Cancel the common factors to get;

$=4\times1 \times \frac{16}{1}$

$=64$

QUESTION F

The multiplication problem is

$11 \times 2 \frac{7}{11}$

Convert the mixed numbers to improper fractions to obtain;

$11 \times \frac{29}{11}$

Cancel out the common factors to get;

$=1 \times \frac{29}{1}$

Simplify;

$=29$

QUESTION G

The given problem is

$5\frac{1}{3}\times 5\frac{1}{8}$

Convert to improper fractions;

$=\frac{16}{3}\times \frac{41}{8}$

Cancel out the common factors to get;

$=\frac{2}{3}\times \frac{41}{1}$

$=\frac{82}{3}$

Convert back to mixed numbers

$=27\frac{1}{3}$

QUESTION H

The given expression is

$10\frac{2}{3} \times 1\frac{3}{8}$

Convert to improper fraction to get;

$\frac{32}{3} \times \frac{11}{8}$

Cancel common factors to get;

$=\frac{4}{3} \times \frac{11}{1}$

Simplify

$=\frac{44}{3}$

Convert back to mixed numbers;

$=14\frac{2}{3}$

7 0

3 years ago

Matt Kaminsky bought a Volvo that is 33∕4 times as expensive as the car his parents bought. If his parents paid $8,000 for their

Mashutka [201]

33/4 is the same as 8 1/4

so that means that matt bought the Volvo for 8 1/4 times as much as the car his parents bought.

therefore... 8,000 times 8.25 = 66,000

8 0

3 years ago

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Find the area and perimeter of each composite figure use 3.14 for pi round your answer to the nearest 10th

Ad libitum [116K]

1. Perimeter is 3 + 3 +3 +4 +5 = 18 feet

Area = 3*3 = 9, 1/2*3*4 = 6, 9 + 6 =15 square feet

2. perimeter = 2.5 +2.5+ 2.5+2.5+0.5+0.5 = 11 meters

Area = 3*.5 = 1.5, 3*2=6, 6+1.5 = 7.5 square meters

3. perimeter = 3.14*2*3 = 18.84 +8 = 26.8 inches

Area = 6*4 = 24 + 3.14*3^2 = 28.26 = 28.26 +24 = 52.3 inches

4. surface area = 2*π*6*20+2*π*6^2= 980.2 yards

Volume = π*6^2*20 = 2261.9 cubic yards

5.surface area = 2*(9*7+2*2+2*9) = 190 cm

Volume = 2*7*9 = 126 cubic cm

6. surface area = <span>2*(11*11+11*11+11*11) = 726 mm</span>

<span> Volume = 11 *11*11 = 1331 cubic cm</span>

7 0

3 years ago

Please help me thank you so much have a great day and also be nice to others and especially yourself

ioda

8 inches because 80/10=8

6 0

3 years ago

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