It depends on the weight of the assignment in the class
The question is simply asking you to evaluate the function for an input value of -3. Meaning we plug in -3 for all cases of n. (-3)^3 + (-3). This gives us -27 -3 which is -30. So g(-3)= -30
Answer:
{-2, -14, -26, -50}
Step-by-step explanation:
The range of the function is the function evaluated at each point of the given domain. So to find the range of the function we need to find the value of the function for each point in the domain:
- For x = -8




The first value of the range of the function is -2
- For x = -2




The second value of the range is -14
- For x = 4




Th third values of the range is -26
- For x = 16




The fourth and last value of the range is -50
Now we can put all the values of the range together
The range of the function is {-2, -14, -26, -50}
Answer:
(a) f(0) = 1
(b) f(3) = 5 (I'm not sure about this one, it's either this or undefined)
(c) f(-2) = 3
(d) 
(e) 
(f) 
(g)
DNE, because the limit of x--> 1 from the left is 2, and the limit from the right is 1. Because they don't approach the same value from both sides, the limit doesn't exist.