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Hunter-Best [27]
3 years ago
6

A cone is inscribed in a right square pyramid. What is the remaining volume if the

Mathematics
1 answer:
diamong [38]3 years ago
4 0

Answer:

3tgfjhihvyuvyuhihhibib

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The number of girls in Mrs. Manning’s classes was 12 less than twice the number of boys. She had a total of 108 students in her
FromTheMoon [43]

40 boys and 68 girls

let's start with variables and an equation.

boys: x

girls: 2x - 12

and we know that boys and girls make up the class. so let's add the two expressions.

x + 2x - 12 = 108

3x - 12 = 108

    + 12     + 12

3x = 120

x = 40 boys

BUT x is only the number of BOYS in the class. so we have to find girls now. let's plug in our value of x into the girls' equation.

2x - 12 = # of girls

2(40) -12 = # of girls

80 - 12 = # of girls

68 girls

let's check our answer!

68 + 40 does in fact add to 108, therefore our answer is correct.

4 0
3 years ago
Mary having her living room and bedroom painted. Interior Designs USA charges $60.00 to evaluate the space plus $35.00 per hour
Lera25 [3.4K]
The last one is correct because 60+35+35+35=165
55+55+55=165
8 0
3 years ago
Which rational number is also an integer?<br> A) -82/6<br> B) -65/13<br> C) 43/5<br> D) 70/25
natulia [17]

Answer:

B

Step-by-step explanation:

Because all of the other ones are decimals and integers are WHOLE number positive or negative, and B is equal to -5

Hope This Helps

6 0
4 years ago
Find the limit. use l'hospital's rule if appropriate. if there is a more elementary method, consider using it. lim x→4 x2 − 16 x
ivolga24 [154]
Probably you are supposed to compute

\displaystyle\lim_{x\to4}\frac{x^2-16}{x^2-4x}

Factorize the numerator and denominator, then simplify:

\displaystyle\lim_{x\to4}\frac{(x-4)(x+4)}{x(x-4)}=\lim_{x\to4}\frac{x+4}x=\frac{4+4}4=2
6 0
3 years ago
Write an equivalent expression for 4(3a+7)+3 (2a+5) if a=5, is the the solution to both expressions the same
Levart [38]
<span>Alternative</span>
4(3*5+7)+3(2*5+5)=
4(22)+3(15)=
(4*22)+(3*15)=
88+45=133

4 0
3 years ago
Read 2 more answers
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