To effectively determine the correct answer, it would be helpful to write this into an algebraic expression. We let x as the number. We do as follows:
<span>Four times the square of a certain number increased by 6 times the number equals 108.
4x^2 + 6x = 108
The numbers can be either of the following since the equation generated was a quadratic equation which has two roots.
x = 4.5
x = -6 </span>
Recall the secant-tangent theorem, and you have
EA^2 = EC*CD
12^2 = 8*(x+10)
and now ED = EC+CD = 8+x+10
I suspect a typo somewhere in the murk above
Answer:
VY
Step-by-step explanation:
Coz they all look the same on the sides
Answer:
Step-by-step explanation:
p^2-8p-9
factor out the trinomial
(p-9)(p+1)
Therefore, she's incorrect. Because (p-1)(p+9)=p^2-p+9p-9=p^2+8p-9 and that's different from p^2-8p-9.
Answer:
Y=-2/3x+6
Step-by-step explanation:
Y=-2/3x+b
2=-2/3•6+b
2=-4+b
6=b
