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maksim [4K]
3 years ago
5

△ABC∼△PQR

Mathematics
2 answers:
Masja [62]3 years ago
8 0
The correct answers are

AB/PQ = BC/QR

∠B ≅ ∠Q

m∠A = m∠P 

the other two are incorrect
AC¯≅ PR¯
BC = QR
slamgirl [31]3 years ago
7 0

Answer:

The true statements are 1, 2 and 3.

Step-by-step explanation:

Given information: \triangle ABC\sim \triangle PQR.

Two triangles are called similar triangles if their corresponding sides are proportional or corresponding interior angles are equal.

It is given that \triangle ABC\sim \triangle PQR, so we get

\angle A=\angle P

\angle B=\angle Q

\angle C=\angle R

\frac{AB}{PQ}=\frac{BC}{QR}=\frac{AC}{PR}

Therefore options 1, 2 and 3 are correct.

The corresponding sides of similar triangles are proportional but not congruent, therefore options 4 and 5 are incorrect.

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You work 40 hours/week for 52 weeks and are given the option to be paid hourly or to go on salary. In which situation will you e
Kay [80]

Answer:

The best possible answer is A) $17.00 and hour with a $1,000 bonus.

Step-by-step explanation:

You can start by narrowing down the answers to the ones with the bonuses. The others are obviously less as it is the same pay without added bonus. Next we can determine the amount in answer A by multiplying the amount per hour by the number of hours in a week and by the number of weeks in a year.

$17.00 * 40 * 52 = $35,360

And then you add the $1,000 bonus.

Answer A Amount = $36,360

Now to find answer D amount, we multiply the total by the 10% bonus to find the bonus amount.

$32,000 * 10% = $3,200

Now we add that to the previous salary to get the overall D answer amount.

$32,000 + $3,200 = $35,200

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8 0
3 years ago
Create an equivalent expression for 13 ^−7 x 13 ^5.
Sveta_85 [38]

13^{-7} \times 13^5=13^{-2}=\boxed{\frac{1}{13^2}}

8 0
2 years ago
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inna [77]
I’m pretty sure it’s 3 and a 2
8 0
3 years ago
When i am solving for the sides of a right triangle when will i use trigonometric functions
AnnZ [28]

Answer:

The ratios of the sides of a right triangle are called trigonometric ratios. We need to use trigonometric functions to find them when we don't have any angle other than 90 degree shown.

Three common trigonometric ratios are the sine (sin), cosine (cos), and tangent (tan). These are defined for acute angle.

However when we have one angle given with the 90 degree we can deduct without trigonometry but we would use all angles to find the hypotenuse or all angles to find the side of a right angle.

Alternatively, we cna do this with one given angle but if we have one, we might as well work out the other one without trigonometry and do a division with Sin = 25 (sin 35) sin 90  / sin 55

is one example when given the base 25ft that would find the hypotenuse or the length of elevation for buildings looking down or zip-wire questions.

Step-by-step explanation:

       A

       |  \

       l     \

4cm|        \ 5cm

       |          \

       |            \

   B | -  -  -  -  \ C      

          3cm

Suppose we wanted to find sin( A) in△ABC    

(The height of the wall in elevation questions would be used above the base shown 3cm at the start) Sin = 3 (sin 35)° sin 90°  / sin 55° to find the height side (4).

Sine is defined as the ratio of the opposite to the hypotenuse

sin(A) =  hypotenuse          ​= AB/BC        = 3/5

             / opposite

                                           

​

​

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Answer:

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